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KTG
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Ans:- 5.61 Hours
Soln:-
v(avg)=sqrt(8RT/piM)
sustituting the values, we get,
v(avg)=630m/s
diamter of earth=12732km=12732000m
therfore, time=12732000/(630*60*60)=5.61 hours
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Kinematics-Eqn I and II
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according to ist kinematic eqn,
v=u+at
But IInd says that
s=ut+.5at^2
here taking out 't' common and dividing we get,
v=u+.5at
What causes the diff of .5 at in both cases
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