Compd is -->
CHO-CH2-CH2-CO-CH3
1->Reduced to n-pentane on clemmenson reduction so carbon skeleton is straight.
2->dioxime so two carbonyl groups
3-> Tollens test->aldehyde
4->iodoform test so in this case->CO-CH3
B->1->ethyl benzeneàKMnO4àbenzoic acidà(soda lime) benzene
2->acetaldehyde +acetaldehyde(aldol formation without heating,using dil NaoH or other base) and then clemmenson reduction(zn-hg +Hcl)
.3->acetone-->(clemmenson reduction)-->2-propanol-->(acid)-->propene
sorry for writing in text.
am new to this.