Messages posted by Parth Chhaparwal

therefore dm = (M/L)dxT - (dT+T) = (dm) W^2 x-Now put value of x = L /4 and 3L/4 and get the result

n = a+b so s = x + y so integral z = x therefore x = L/4 and 3L/4.........this method is direct

depends on the ref point chosen [[middfig]]

<3 <3 <3 <3 <3

yaaas., as a body is indivisual of vectors

ye sirf ek ya 2 number ke liye lagoo hai!! 99% numbers ke liye kaam ka nahi hai.... example..... 100 * 100 = 10000 lekin tere method se 211211 aata hai!!!! teri baara ki dher!!

simple!!a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 +b^2 +c^2 -ab-bc-ca) As a + b + c = 0, then a^3 + b^3 + c^3 - 3abc = 0Therefore a^3 + b^3 + c^3 = 3abc

simple!!a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 +b^2 +c^2 -ab-bc-ca) As a + b + c = 0, then a^3 + b^3 + c^3 - 3abc = 0Therefore a^3 + b^3 + c^3 = 3abc

if n is even, then it will be a perfect sqr but if n is odd then it will not

224 litres

Third

Hey , why r u all blaming the govt, if you really want to show them that their decision is wrong, then prove it by doing much better than we were doing before. So guys, r u wid me?

awesum question, rate me for this comment, n answer is 1

THE NATIONAL COUNCIL OF EDUCATION RESEARCH AND TRAINING HAS BROUGHT REFORMS IN THE NTSE EXAMINATION. NOW, NTSE WILL BE HELD IN CLASS 10 INSTEAD OF CLASS 8. THEREFORE THOSE WHO GAVE NTSE IN 8TH IN 2011 AND 2012 WILL NOW GET ONE MORE CHANCE TO GIVE NTSE IN CLASS 10TH. WE ARE THE CHOSEN ONES, WE ARE GETTING 2 CHANCES. NCERT HAS ROUGHLY DESCRIBED THAT NTSE WILL BR COVERING ALL PARTS OF CLASS NINTH AND CLASS TENTH. THIS MAY INCLUDE CONCEPTS FROM CLASS 11TH AND 12TH TOO.

I AM CURRENTLY A STUDENT OF CLASS 9TH AND IM STUDYING AT FIITJEE IN THE PROGRAM

'4 YEAR CLASSROOM PROGRAM FOR IIT JEE'

CAN ANYONE SUGGEST METHODS FOR PREPARING FROM THE FORTHCOMING EXAMINATION?

PARTH CHHAPARWAL

I am in class 9 and had my phase test on 8 july

distance in th second is equal to u + (a/2)[2n - 1]Here, 10 = 5 + (a/2)[2*3-1]1 = a/2a = 2Therefore acceleration is 2 m/sKya baccho waala sawaal thaa!!

weight of 1 oxygen atom = 16 amu.oxone = O^3 = 16 x 3 = 48 amu.Therefore,48 g of ozone = 1 avogadro number = 6.0223 x 10^23.In this question, NTP is just for confusion!

by using a universal indiucator such as litmus, turmeric, etc...

Does any1 have a WORKING link for the ebook of HC Verma without passwrd n even if it has a password can u specify the CORRECT password?

iit guwhatti

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