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Its simple. I have shown the mechanism in the figure. All the steps are simple and the conversion of oxime to caprolactum is by Beckmann Rearrangement.

So, the day has finally arrived. I am taking a voluntary retirement from goiit.

Why??? I myself dont know the actual reason but I just felt that its the right time to do so.

This site has helped me a lot. I asked lot of my doubts here and almost all of them were cleared by you goiitians to my total satisfaction. I learnt a lot of new things, new concepts and all this really helped me with my preperations.

I wud like to thank everyone who appreciated my work/replies(sorry but I wont be writing their names, the list is too long and I am afraid if I miss anyone, he/she might feel bad) and also those who criticised me. NO hard feelings for anyone. I admire my critics as they indirectly help me in my improvement.

It has been a splendid journey till now.

And plz, one request- No need to workout ur scientist/detective brains searching reasons for my retirement. I dont want to blame it on anyone and I wish the same from you. Its completely a voluntary decision.

I dont think that it is a permanent retirement.

I hope to be back some day.

Till then,

Study well

All the Best

Sayonara!!!

LOL. Gud one.
And I think I already know a couple. :P
Hahaha

Bond length is inversely proportional to bond order.

Bond order = 1/2(Nb-Na)
Nb=electrons in bonding mol. orbital
Na=electron in anti bonding mol. orbital

In case of NO and NO(-), the extra electron enters the anti bonding mol. orbital and hence the bond order decreases and bond length increases.

Mr Bladex/chem genius or whatever,

Now I hav a sure shot answer to ur crappy question and that too from the Maestro Dr. P. Bahadur.

When I asked this ques to him, his first reaction was-''Yeh kaisa bevakoofi ka question hai''. SO it proves that your question is just crap.

But still, the answer given by him-

All the colligative properties depend upon the number of solute particles present in the solution. There properties arise due to the bombardment by the solute particles. So, it itself means that we dont need to bother about the solvent.

Always remember- Osmosis is not due to osmotic pressure. Osmotic pressure is due to osmosis and osmosis happens by virtue of movement of solute particles.

And about my previous explanation-It was correct too.

We cant define concentration of solvent in a solution of a solvent and a non volatile solid solute. Concentration of solvent can be defined only when it is pure solution. For example-molarity of water in pure water is 55.55

So, watever he explained me, I hav posted it here and I cant doubt his answers and I dont think many ppl wud dare to give a second thought to his answers.

So now whatever explanation you give, atleast I am not gonna give a damn either to the ur answer or to you!!!

Well, dude.
Maybe I am drunk but I think you are also out of ur minds this time.

How can u take the example of liquid and alcohol?????

For ur kind information, osmotic pressure can be found only when solute is non volatile solid NOT a liquid.

Buddy,
U R confused.
Concentration is defined only for that substance which not present in excess.
Concentration means- How much substance is present in some excess solvent.

How can u define concentration of solvent????????
Conc=moles/volume

If u try to define concentration of solvent, then whose volume wud you take?????
U cant take the volume of solute becoz it is present in very small amount.

Hope you get it!!

See, just find the oxidation state of C in each case.
More the oxi state, more it is oxidised.

For finding oxi state, consider each bond to be ionic.
Now O>C>H(electronegativity)

So in R-COOH
Oxi state of C = +3 (+2 from C=O and +1 from C-OH)

And in CH2OH
oxi state of C= -1 ( -2 from 2 C-H bonds and +1 from C-OH)

So C is more oxidised in COOH

What's so difficult in this ques?????

Take for example CH4. Here C is in -4 oxi state.
Now take its halides.
CH3X-oxi state= -2

CH2X2-oxi state= 0

CHX3-oxi state= +2

CX4-oxi state= +4

So you can clearly see that oxi state of C in every halide is more than that in hydrocarbon. And increase in oxi state means oxidation. :)

Well, its pretty much clear from the mechanism.
U cant get anything else other than Primary amine.

I dont know what do u mean by CH4=1
but if it means that this compound's V.D. is 4 times that of CH4, then this ques is pretty simple.

See, Molecular weight = 2 x V.D.
Let V.D. of CH4=v
Mol wt = 16
therefore v=8
Now the VD of the given substance is 4v = 32

Therefore its mol. wt = 2 x 32 = 64

Hope U get it.

The flash point of a flammable liquid is the lowest temperature at which it can form an ignitable mixture in air. At this temperature the vapor may cease to burn when the source of ignition is removed. A slightly higher temperature, the fire point, is defined as the temperature at which the vapor continues to burn after being ignited. Neither of these parameters are related to the temperatures of the ignition source or of the burning liquid, which are much higher. The flash point is often used as one descriptive characteristic of liquid fuel, but it is also used to describe liquids that are not used intentionally as fuels.

Source- Wikipedia

I think the answer is 70cm from the source.

Look at the figure. The last reflection of a ray coming out from the source S can take place only from the tip of the mirror and by similarity and congruence of triangles, you can easily see that maximum distance from the source = H/2 + H/2 = H

Hope I am correct.

Well, ya its Ethylene Diamine Tetra acetic acid

Its structure is shown in the figure.

Volume occupied by 1 mole of water, means 6.022 x 10^23 molecules = 18 cm^3
So volume occupied by 1 molecule = 18 / (6.022 x 10^23) cm^3