This is the solution. I am taking g=10m/s^2.
Ei=mgh=mg5sin37=60
Ef=1/2 k x^2=k/50 (x=0.2)
Change in energy=work done by external force (which is friction here)
so, k/50 - 60 = -mu mg 5cos37
k/50 - 60= -80 mu --------------------------------------------(1)
Now while going up-
Ei=1/2 k x^2 = k/50
Ef= mgh= mg 1 sin37 = 12
Therefore, 12 - k/50 = -mu.mg.1.cos37
12 - k/50= - 16mu -------------------------------------(2)
On solving (1), (2), we get mu=0.5
put it in any one of the 2 equations, we get k=1000
Rate if satisfied. Nudge me if not understood.