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thanks to all.i now got it right
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A little addition
Scalars can be added algebraically. For example 5 kg + 2 kg = 7 kg.
But vectors have different rules of addition, multiplication etc.
Current have direction ( +ve to -- ve conventional sense) but it is a scalar.
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I found the following link very much. If it helps, I repeat helps, give a salute to the author and please don't forget to rate me.
http://www.goiit.com/posts/list/community-shelf-iitjee-is-too-easy-5175.htm
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hey i too agree with arora.matter must have mass,but does fire? i wonder
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Final vel = 0 (v)
initial vel = u = (gR)1/2
height= h
v^2 = u^2 --2gh (u and g are opposite)
or, h = u^2 / 2g = gR / 2g = R /2
option b is correct
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hey this method appears better
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i solved such sums in my tenth class.and i m sure shikar's method will work easily
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thanx.it will be very useful
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Given
(cos^4 x ) / (cos^2 y) + (sin^4 x) / (sin^2 y) = 1
or, (cos^4 x ) / (cos^2 y) + [(1-cos^2 x)^2] / (1-cos^2 y) = 1
or, cos^4 x -cos^4 xcos^2 y + cos^2 y + cos^4 xcos^2 y - 2cos^2 xcos^2 y
= cos^2 y - cos^4 y
or, cos^4 x- 2cos^2 xcos^2 y + cos^4 y = 0
or, ( cos^2 x - cos^2 y)^2 = 0
or, cos^2 x = cos^2 y -----------------------------------------(1)
Similarly
sin^2 x = sin^2 y -----------------------------------------(2)
now
(cos^4 y) / (cos^2 x) + ( sin^4 y) / ( sin^2 x)
= (cos^4 y) / (cos^2 y) + ( sin^4 y) / ( sin^2 y) [ using 1 and 2 ]
= cos^2 y + sin^2 y
= 1
Rate me if you like.
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we know -1<sin x<-1
0 < sin(sinx) < sin1 . why?plz explain even if the question seems silly.
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we know -1<sin x<-1
0 < sin(sinx) < sin1 . why?plz explain even if the question seems silly.
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The r.i. depends on the wavelength i,e, color of the light. So the focal length also varies with color. Thus when white light ( all wavelength ) is used each color forms a seperate image of the object. This is Chromatic aberration.
For further reading refer H. C. Verma vol I, page 400.
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viscous force = 6  r v
wt of the sphere = volm * density = (4 pi r^3 sigma)/3 sigma = demsity
wt of the displaced liquid = (4 pi r^3 raw)/3 raw = demsity
equate we get the equn given by Asmita
And she is correct.
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Zero.
SHM can also be considered as a projected circular motion. In one period the particle completes the circle, i e comes back to the position from which it started.
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ab=a+b is the given data
now
a/b +b/a --ab
=(a^2 +b^2)/ab --ab
= [ (a + b )^2 --2ab] /ab --ab
= { a^2 b^2 --2ab } /ab --ab [ using ab=a+b]
= [ a^2 b^2 --2ab -- a^2 b^2 ] / ab
= [ --2ab] /ab
= --2
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It is a bound state problem and the condition for that is n < 1.
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