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no...iodoform test is given by alcohols of form CH3-CH2(OH)-R
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sorry...MI of semi circular disc is mr^2/2 as told by karthik
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theoritically no...but practically there is a finite max possible temp.
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beta rays are not electro magnetic waves...they are just stream of electrons
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the change in momentum caused due to the gravitation is very negligible wen compared to the momentum changes produced due to explosion
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the MI of the disc given by arjun virmani is correct...its given for the semi circular disc
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there are some positively charged ligands like NO+
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wen the field is suddenly switched off there is a change in magnetic flux wich produces induced electric field...integral(E.dr)=-d@/dt...where d@/dt is the rate of change of flux...now integral E.dr=E.2(pie)a...d@/dt=(area*dB/dt) where db/dt is the rate of change of field...now we get E=(a)db/2dt...multiply by charge on both sides...then qE=F...we get the force acting on the ring...then mdv/dt=F....dv=rdw ...solve the three equations
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use the kirchoff's loop law and find the current in the circuit as function of time...it will b a exponential function...i=i0(1-e^(-Rt/L)) where i0 is the max current....from the equation we see that at t=0 i is zero and at infinite time current attains a steady value
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the equation tells the position of the wave with time....say if u keep the time to b constant,then the equation gives the displacement of each particle from the mean position along the length...if we keep distance of the particle to b fixed,ie if we take one single particle the equation gives the displacement of the particle with time from the mean position
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Fe2O3(s) + 3?H2O + 2?e? 2Fe(OH)2(s) + 2?OH? ?0.86
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na2co3 wen heated to high temperature decomposes
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ph=pka+log(conc of salt/conc of acid)...wen half neutralised the acid conc. is equal to salt conc....so ph=pka
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draw a circle with the point of intersection of the two mirrors as center and distance of object from this point as radius...now take the reflection of the object in one of the mirror...the image(i1) lies on the circle behind the mirror(m1)...now take an image of the image(i1) in the mirror m2....the image i2 is formed behind the mirror m2...continue the process till the the image is formed behind both the mirrors...a general formula for the no. of images is derived from this method...i hope u understand...
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an inductor is usually a coiled wire.when there is change in the current passing through the coil, an induced magnetic field is produced in which the energy is stored
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energy radiated is initially u1=e(sigma)AT^4....A is area of the sphere and sigma is a constant....A1=4(pi)R^2....u1=300w.....wen half of the sphere is blackened energy radiated is u2=(1)(sigma)(A/2)T^4+e(sigma)(A/2)T^4...the emissivity of the half part that is darkened is 1 and the other half is e......divide the two equations and get the value of e
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velocity of the body wen it strikes gound=(2gh)^0.5..........find the velocity after rebound...use the k.e relation given
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as altitude increases temperature decreases
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i guess it is due to adsorption of the carbon particles on the surface of eraser
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