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 ROHAN KUMAR's messages in the community 1 2 3 4 5 6 7 8 9 10 GO Go to Page...
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i have also qualified for isi:: indian statistical institute for b.math course ..... i also want to know what is the quality of this college and for iiit whether i have to fill the form or not
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i can wait till 3rd counselling then can i get any iiit
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FOR BITSAT IT IS PCM ONLY
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I GET 6981 RANK IN CATEGORY RANK AND OVERALL 33500 RANK AND STATE 2041 RANK. WHAT ARE AVAILABLE OPTIONS FOR ME? AM I APPLICABLE FOR IIIT
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ans is(B) simple methods are (1)AS U SHOULD KNOW THAT MIN. VALUE OF ax^2+bx+c OCCURS AT x=-b/2a (2) SIMILARLY IN THIS QUESTION MIN. VALUE OF FUNCTION OCCURS AT x=-p/2 SO BY PUTTING IN WE GET Ymin = - p^2/4 + q (3) AS IT IS GIVEN THAT Ymin=O SO q=p^2/4
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i belong to obc category
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can anyone tell me what is the use of category rank in counselling through aieee?

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I DON'T THINK SOIT WILL AFFECT RANKING AND COLLEGE SELECTION
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U HAVE OPTION TO DROP OR CHECK THE SPOT ROUND IN WWW.CCB.NIC.IN
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WHAT  TYPES OF QUESTION ARE ASKED IN ISI INTERVIEW? ISI::::( INDIAN STATISTICAL INSTITUTE)

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WHAT  TYPES OF QUESTION ARE ASKED IN ISI INTERVIEW?

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please tell me the method @ronnie
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DETERMINE THE LARGEST NUMBER IN THE INFINITE SEQUENCE   1,21/2,31/3,41/4.......................n1/n

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yes they can show as cis and trans forms of a compound is considered as diastereomers
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@jagdish I think your last step is wrong as by putting y=o in f(0,0)=1=f(-1,1) which is same as the first condition ..... please solve it question is not wrong
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ANS. IS PIE U WILL GET BY DRAWING GRAPHS WHOLE EQUATION CAN BE WRITTEN AS (X-1)^2+3 = -3COS(ax+b) draw the graphs of (x-1)^2 + 3 and -3cos(ax+b) find the point of of intersection u will get your answer ,........................... shortcut minimum value of L.H.S occur when x=1 so put x=1 then u will get your answer
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I DON'T UNDERSTAND SIR PLEASE EXPLAIN ME LITTLE BIT MORE
 Discussion Forums -> This Post 5 points    (1    in 1 votes )   [?]
I CAN TELL THE STEPS JUST DIVIDE AND MULTIPLY THE EQUATION WITH 2SINPIE/65 AND THEN U MUST KNOW THAT 2SINX*COSX =SIN2X THEN AGAIN MULTIPLY AND DIVIDE WITH 2 AND AGAIN AND AGAIN......... U WILL GET YOUR ANSWER
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