Messages posted by ROHAN KUMAR

i have also qualified for isi:: indian statistical institute for b.math course ..... i also want to know what is the quality of this college and for iiit whether i have to fill the form or not

i can wait till 3rd counselling then can i get any iiit

FOR BITSAT IT IS PCM ONLY

I GET 6981 RANK IN CATEGORY RANK AND OVERALL 33500 RANK AND STATE 2041 RANK. WHAT ARE AVAILABLE OPTIONS FOR ME? AM I APPLICABLE FOR IIIT

ans is(B) simple methods are (1)AS U SHOULD KNOW THAT MIN. VALUE OF ax^2+bx+c OCCURS AT x=-b/2a (2) SIMILARLY IN THIS QUESTION MIN. VALUE OF FUNCTION OCCURS AT x=-p/2 SO BY PUTTING IN WE GET Ymin = - p^2/4 + q (3) AS IT IS GIVEN THAT Ymin=O SO q=p^2/4

i belong to obc category

can anyone tell me what is the use of category rank in counselling through aieee?

I DON'T THINK SOIT WILL AFFECT RANKING AND COLLEGE SELECTION

U HAVE OPTION TO DROP OR CHECK THE SPOT ROUND IN WWW.CCB.NIC.IN

WHAT TYPES OF QUESTION ARE ASKED IN ISI INTERVIEW? ISI::::( INDIAN STATISTICAL INSTITUTE)

WHAT TYPES OF QUESTION ARE ASKED IN ISI INTERVIEW?

please tell me the method @ronnie

DETERMINE THE LARGEST NUMBER IN THE INFINITE SEQUENCE 1,2^1/2,3^1/3,4^1/4.......................n^1/n

yes they can show as cis and trans forms of a compound is considered as diastereomers

@jagdish I think your last step is wrong as by putting y=o in f(0,0)=1=f(-1,1) which is same as the first condition ..... please solve it question is not wrong

answer is 4

PLEASE HELP!!!!!!! I AM TRYING BUT I AMNOT GETTING ANY FUNCTION

ANS. IS PIE U WILL GET BY DRAWING GRAPHS WHOLE EQUATION CAN BE WRITTEN AS (X-1)^2+3 = -3COS(ax+b) draw the graphs of (x-1)^2 + 3 and -3cos(ax+b) find the point of of intersection u will get your answer ,........................... shortcut minimum value of L.H.S occur when x=1 so put x=1 then u will get your answer

I DON'T UNDERSTAND SIR PLEASE EXPLAIN ME LITTLE BIT MORE

I CAN TELL THE STEPS JUST DIVIDE AND MULTIPLY THE EQUATION WITH 2SINPIE/65 AND THEN U MUST KNOW THAT 2SINX*COSX =SIN2X THEN AGAIN MULTIPLY AND DIVIDE WITH 2 AND AGAIN AND AGAIN......... U WILL GET YOUR ANSWER

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