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hey guys does ne 1 know here about the world cyber games
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dude,,this was there in goIIT even b4 2 yrs,,,,,what say?,,,,,,,no1 owns it,,,,,,,,,+10,,,,,,,,,,:P
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lol what????? book for algebra?????? Hall and knight is good
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O-P-T-I-C-Sis an english word and has no full form:P
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hi im telling u a good link where all these problems have been discussed in gr8 detail
http://www.chemguide.co.uk/physical/acidbaseeqia/phcurves.html#top
and another extremely good sit
for tribasic acid concept
http://www.wpbschoolhouse.btinternet.co.uk/page07/equilibria6.htm
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well lemme tell all u ppl that only 3 students were responsible for compilation of all these questions
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yes ive got 99%
maths 100
science 100
english 99
Sanskrit 100
I.T 100
Social studies 95
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look im giving u da correct soln im telling u textbook method  f(x)dx =g(x)+c , then now see f -1(x)dx we put x=f(t) dx=f`(t).dt f -1(x)dx = tf `(t)dt use integration by parts we get =tf(t)- f(t)dt f(t)dx =g(t)+c =tf(t)-g(t)+C t=f-1(x) so we get xf-1(x)-g(f-1(x))+c so (c) is correct
please check whether there has been any mistake in the question if it is (a) then there is no function of g(X) in it
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please check the study material provided at GOIIT
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both are good and engaging
listen to ur heart!
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hey havnt
i answered it.!!
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in brochure it is written board percentage not PCM ---------------------------------------------------------------------------- Q-is i am eligible ans-are yes you are eligible  |
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the book TMH is for those who understand the basics
TMH is question solving book the theory theyt give is inadequate.
u should learn first the basics from NCERT,ML Khanna too is good l
u can use this site too
http://www.goiit.com/chapters/tutorial/maths/complex-numbers.htm
it covers basics well and i got a lot from it.!
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look joy we have to use basics for such questions rather than equations!!
when we take case of slip down friction acts on opposite side i.e up and when it skids up friction acts at downdard to the banking ------------------------------------------------------------------------------------ the road has been banked so the angle tan  =v 2/rg v=10m/s r=20m g=10m/s2 from here we get tan =1/2 ------------- Case 1:-slips down direction of friction is opposite to motion we take components of Normal reaction and friction forces along vertical and horizontal axis N(cos +  sin )=mg ----------1 divide eq 1 and 2 and calculate v Case 2:-skids up direction of friction is opposite to motion we take components of Normal reaction and friction forces along vertical and horizontal axis N(cos - sin )=mg ----------1 divide eq 1 and 2 and get v hope it helps
!!
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if u want good books in theory
then take Concise inorganic chemistry by J.D lee
and i also know a good small book recommended by experts for
beginners
they are
Language of chemistry and chemical equations by G.D tuli
for questions U may take TMH or arihant books for solving
many say that TMH are more concise and have less out of course questions.
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hey shivamk
i want to tell u a very important
fact
f(x) and g(x) are two differenciable,continuous functions
then f(x) +g(x) is differenciable everywhere
and if f(x) and g(x) are two non differenciable functions (but at same place)
then f(x) +g(x) is differenciable
only when both non differencial elements oppose each other
i mean they cancel the bend in the graph!!!
use basics to be correct everytime
i.e left hand derevative=right hand derevative
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yaar wid 230 u shd expect below 4000 4 sure
but NIT trichy is popular so it will be tough
who knows u may well make it!!
depends on which course u wanna take
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well i have hrd frm my brother who studiesat AMITY that amity university does not need AICTE approval
but ya it needs UGC approval so that its students after doind Btech
can apply for GATE and other exams
UGC team will visit amity in coming days!!
who knows they may get it!!
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im telling u a good way of solving such questions
we take v=(ucosQ) i + (usinQ-gt) j
i,j are unit vectors to x,y axis
Q is angle made with the ground
and the point from where the particle is thrown as origin
so the equation of the
inclined plane in 2-D is
y=(1/sqrt(3))x
we tale vector m=cos 30 i +sin 30 j
this is unit vector along plane
we know the angle at which it hits the plane
wetake dot product of v and m
v.m=|v||m|cosF
where F is the final angle at which it hits the plane
hope u get it!!
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sorry for not typing the solution(it was too late night) just putting sol in some time. ------------------------------------------- a(a^2 - 3b^2) = 2 ;
b(3a^2 - b^2) = 11;
now as i had said put a=rsinQ b=rcosQ we get r3SinQ(1-4cos2Q)=2-------1 r 3CosQ(3-4cos2Q)=11----------2 divide eq 1 and 2 tanQ(1-4cos2Q)=2/11(3-4cos2Q) now gather terms of cos2Q we get (tanQ-6/11)=4cos2Q(tanQ-2/11) sec2Q(tanQ-6/11)=4(tanQ-2/11) put sec2Q=1+tan2Q now put tanQ=t we get the equation 11t3-6t2-33t+2=0 now put it like this 11t3-22t2+16t2-32t-t+2=0 11t2(t-2)+16t(t-2)-(t-2)=0 so t=2 is a factor that means tanQ=2 sinQ=2/sqrt(5) cosQ=1/sqrt(5) using this we conclude that answer is 5
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