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oops sorry about that R2, my mistake...now the sol. is corect man...
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Imagine a charged plate with -ve charge on it. From the surface of the plate a +ve charged particle is projected. It reaches the max. height and stays there instantaneously.now, its having electrostatic P.E. Now if the charged plate is removed what would happen to the state of motion of the body? Would it move or would it just stay there. What happens to its P.E. and principle of energy conservation?
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for more conceptual ideas read Richard Feynman's The Feynman Lectiures on Physics...that book simply rocks.
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Well, when the body moves from infinity to some point in the space without any help of any external force(it can do so if you place it at the so-called infinity boundary and jiggle it a bit), the gravity does +ve work on it and its KE increases and this would be equal to -ve of change in gravitanional P.E = -(-GMm/R-0) = GMm/R. But when you move it using a force directed against the gravitational force, its KE gets decreased as the force does negative work on it, hence  K.E = -P.E + Wexternal. It should be noted that in any case the W done by garvity remains the same no matter what bloody darn force acts on it W = -P.E. The work done by the force is K.E + P.E
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Is there any good book on organic chemstry which has the GOC part( hyperconjugation, resonance and such stuff) explained rather well. Please avoid references to books like Arihant, MTG, Dinesh etc...
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the problem is that when u consider the case of 3 gals being together u will be counting the case when 2 gals are together again.
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hi, pls look @ my solution:::
the children can be arranged in 8! ways.after that we have 5 places in b/w of which 3 can be used by the grandfather. hence grndchdrn + grndfthr + others can be seated in 8! x 3C1 x 4! ways i.e, 2903040 ways.
****XXXXX****
* - children
X - grandfather and others
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If u r talkin about the book by J. Clayden, the book is useful only to pro's in Chemistry. But its one heck of a book.!
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I haven't seen such a great book in physics as this. Must for physics freaks.!!!
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Great book i read this almost every day. You get really interested in Chemistry after this.
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Let the force applied be F. Then, acceleration of the rope is F/m. Since the rope is uniform, the force acting on the mid-point will be 1/2 m * F/m = F/2. Hence, ratio is 1:2
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SPEC is considered best for IIT JEE(i'm a student). ppl have even moved from PC to SPEC. Mathematics and Physics is really superb while chemistry lags behind...
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dat's the q. from FIITJEE RSM. read through the sol. or just consider equilibrium
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I don't find any special mention of inequations in the prescribed syllabus of JEE. But I do find such a chapter in TMH and K.D.Joshi(Educative JEE Mathematics). Is it really included in the syllabus?
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The answer is correct only if the acceleration is in km/min2
Let the body travel for a distance x1 for a time t1 with acceleration a1. And, let the body travel for a distance x2 for a time t2 with deceleration a2. The max. velocity reached by the body is v = a1t1. But from 0 = v - a2t2,(the final v is zero),
v = a1t1 = a2t2 or rearranging
t1 + t2 = v/a1 + v/a2 ( t1 + t2 = 4 min)
or, 4 = v/a1 +v/a2 -------------------(1)
from the eq. v2 = 2a1x1 and v2 = 2a2x2,(The final velocity is zero...)
x1 + x2 = v2/2a1 + v2/2a2( x1 + x2 = 4 km)
or 4 = v2/2a1 + v2/2a2 ----------------------(2)
dividing (2) by (1) and solving
v = 2km/min.
Putting this in eq (1) 1/a1 +1/a2 = 2
Hence proved.
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