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yes 1.1 e-7 is 110nm which uv radiation
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right answer. good job mister genius
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jst dont know d formula to be used ,faced dis type of ques for d first tym
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Ans b) is correct
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joyfrancis i am unable to get a clear physical picture of your problem. Are there more than one tracks? What is the role of other tracks etc.? If possible please give the figure of problem
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it will be 3l/2. ou want velocity of block to become sqrt(3*g*l)
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Good search vagee
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if dilectric constant is not givev we can take it 1(for something with this high dilectric strength it should be of that order).
q should be such that its field is less than 2.7e6.
q=2.7e6*(0.5)^2/(9e90=75 microC as given by chinvora
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hi akash i think lets not discuss questions like this, as the whole physics will fail if some one can move with speed of light. So giving any answer for this problem will be just a speculation and nothing more
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let d1 be distance bewen fish and interface and d2 be distance beteen bird and interfac. so apparent distance of bird from fish
d= d1+n*d2
differentiating we ge
v=v1+n*v2
or v2=(v1-v2)/n=(17-5)/n=12/n. for water it is 9m/s
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ans given is remains constant
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see in organ pipe wavelength will remain same. But as temperature increases velocity of sound increases and ence frequencies will increase. As beat is difference in frequencies of two pipes it will also increase
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right answer by rocker ony that actual reflected ray will be above as pointed by pragna
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good answer nik
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for this you will have to see the hubble's law. it says velocity os sep v=H*d where d is distance beteen bodies and H is constant and its value is 71km/sec/mega parsec. for earth and sun this velocity comes out to be about 1-^-11 Km/sec.
So no need to change distance
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Hi friends, i am sorry but i was unable to see his yars iit paper. Can any one post the exact figure. But still i want to make some points on the basis of above discusions
i) If it a cavity then we cannot assum charge inside it unless it is given that there are charges kept there.
ii) To find electric field in the cavity we will take a surface insied the cavity. A surface outside the cavity calculate flux E.ds at points which are not inside cavity.
iii)if cavity is present at the center and rest charge is arranged uniformaly around it then field inside it is zero.
iv)if cavity is not present at the center then electric field inside cavity will b non-zero, but i think it will be non-uniform in general
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A POSSIBLE SOLUTION OF GLOBAL WARMING
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Let me approch the question from very basic. If we change earth's orbital radius from r o kr, th energy reachinf eart will change from E to E/k^2. As this is also equal to energy emited by earth which is proportional to T^4 so the temp will change from T to T/sqrt(k). As present temp of earh is about 280K to make it 275K k should br (280/275)^2 which is about 1.037. So to decrease temperatur from 280 to 275 earth's radius should increase by about 3.7%
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