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two charges Q and Q are placed a distance x apart. a third charge q is placed in between them such that the three charges are in equilibrium. what is q in terms of Q ?
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It is a scalar because it does not follow the laws of vector addition, and adds up just like scalars. for example, 5 ohms + 5 ohms is 10 ohms regardless of the direction of the two currents and the angle between them. So current is a scalar quantity.
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id a function is continuous and takes only rational values, then t must be a constant function. therefore f(1)=f(2)=f(3)=........ therefore the equation becomes x^2+2x+3=0. therefore complex roots
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cos2x= 1- 2(sinx)^2 so..... 3cosx-(sinx)^2=0 implies... 3cosx -1 + (cosx)^2=0. soo after solving, u'll have cosx= (0.5)[-3+sq.root(13)] or cosx= (0.5)[-3-sq.root(13)] only one of these lies in between -1 and +1. so there is just one solution...
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i dont think sooo. but remember this- mirror and lens formulae are applicable only for thin lenses or mirrors
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if 90 is in degrees, it is 1. but since u didnt mention anything, it means 90 radians. sin1= 8.41470984807896505 * 10^(-1)
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it's actually a convention. according to the above proof, even (-1)! = 1. (if it makes sense). the no. of ways we can arrange n objects taking all at a time is n!(i.e. no. of permutations is n!) . that is nPn= n! using the formula, n!/(n-n)! = n!. therefore 0!=1. otherwise u can also do a similar thing with combinations.
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light is a form of energy. it helps us see. according to wave theory of light, light is an electro-magnetic wave. that is it has both electric and magnetic fields.according to particle theory of light, it consists of photons (energy quanta or energy packet)...
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alkanes have only single bonds whereas alkenes have atleast one double bond
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is i =sq.root(-1) or i = (plus or minus) sq.root(-1) ???
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the function is one-one so there does exist an inverse to this function. but i don't know it
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there is no speific method for solving a cubic equation.
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go to the above link to download microsoft mathematics for free. i saw the graph but... i didnt find anything special about that.u forgot to mention x>0.
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suppose g(x) = a.f(b.x+c) + d how can we get the grapgh of g(x) from the graph of f(x). Should we go in the order a,b,c,d ; should we first apply transformation b, then c, then a, and then d ; or can we apply transformations in any order ??
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0 kelvin not -273 kelvin @ Viraat Gupta
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(tanA+tanB)/(1-tanA.tanB)
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Vriti Edustore
