Messages posted by akshara

thnx tarun n harsh.i got it

S.its 20ft/s2.can u please give me the method to solve this

its from H C VERMA

its not 2ft/s2

BO=1/2(10-6)=2

i dont know.i dint get the answer as 70.its given in the book as 70

two trains moving parallel to each other started from same station.First train with acceleration of 0.5m/s2 and gets maximum velocity of 22m/s.After 40s second train started with acceleration of 1m/s2 and gets a maximum velocity of 44m/s.Find out the time after which second train catches the first

even i got 10.but the answer is given as 70m/s

ur answer is wrong

if its toooooooooo easyyyyyyyyyyy give me the answer with method

a= gsin theta+mu g cos theta

A body starts with a initial velocity of 10m/s and moves along a straight line with a constant acceleration.When the velocity of the particle is 50m/s the acceleration is reversed in direction.Find the velocity of the particle when it reaches the starting point

A lift is descending with uniform acceration.To measure the acceleration,a person in the lift drops a coin at the moment lift starts.The coin is 6 ft above the floor of the lift at time it is dropped.The person observes that the coin strikes the floor in 1 second.Calculate the acceleration of lift.

Obviously H C VERMA

if it is XeOF4 it will be square pyramidal due to sp3d2 hybridization as there is a lone pair on Xe atom

sorry its 1,2 dibromobenzene

Its i,2 dibromobenzene

I think it is tetrahedral due to sp3 hybridization

sp2 hybridization and 1 lone pair on the central atom

If a,b,c,d E R such that a

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