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Intramolecular H-bonding is present in o-nitrophenol. In p-nitrophenol, the molecules are strongly associated due to the presence of intermolecular bonding. Hence, o-nitrophenol is steam volatile.
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let the eqn of the line be "x cos(w) + y Sin(w) = p (remember the normal form of st line in xith class, where eqn of line whose distance from origin is 'p ' and 'w ' is the angle which perpendicular from origin makes from +ve side of 'x ' axis is x Cos(w) + y Sin(w) = p OK?
now to form diff eqn of above line, we have two unknown constants i.e. 'w ' and 'p ' so we need to differentiate it two times (as there are two unknown constants.)
Ist diffrentiation of above eqn w.r.t. 'x ' gives, cos(w) + Sin(w) dy/dx = 0
2nd diff of bove eqn gives, 0 + Sin(w) d2y/dx2 =0 => d2y/dx2 =0
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which is more stable and why
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