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i had a frnd in kota in bansal classes with me....initially in 11th he was so poor that he cud not even get selected in vibrant academy and was in 43rd batch in bansal....throughout 11th he remained in that zone only.....but in 12th he studied hard....he gave much importance to maths.....got promoted from 43rd to 4th batch in 12th only on the basis of maths and some physics....in 12th also remained in 4th with me and was only enthu in maths....after dec....only 3 months for jee with boards also did the pending work.... learned whole chemistry did physics....and remained in touch with maths.....cleared JEE with some 3500 rank now in IIT vanarasi chem. engg.....so just relax....and enjoy maths along wid learning physics and chem!!!!maths is something really hard for most people to learn throughout syllabus upto JEE level in 3 months!!!!so better master over it now....All the BEST!!!!
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ofcourse u can....its very rare and hard to remain consistent....so that happens....no worries abt that.....i guess u must be in 12th right now....so u have ample time now....first thing is never leave maths....whatever b d conditions of other subjects never ever take maths for granted....u must be at ur best in maths all d time....phy and chem....u can do that alternatively and simultaneously also....so u can get the best rank too....so relax and study hard!!!!
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yup....doing eletronics and comm.engg
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hii again.... i joined goiit an year back when i was all down with my poor show in JEE and AIEEE.. never thought to drop an year but always had this ques...where do i utilise what i studied in those 2 years?? i prepared very hard but cud not clear any exams properly due to panics in exam time..this thing is very common with students..many suffers from mental doubts and lows rather than academic doubt..i researched on it for months..finally m there to help u all again....feels like my family!! took admission in NIT Raipur..got busy there..but it ws all scrambled!!!! i was one the active members on d site those days.... yesterday one of my frnd suggested to join back this site....to get back everything i always wanted to do!!!!question and discussions.... i am really inspired by the curiosity of brain.. when i see the question people ask.....it gives an immense pleasure of being educated and to learn and make people learn..... m really happy to be back again....!!!!! never stop askin ques....do whatever u want.....go to the limits but ask for what u want....dont ever give urself a chance for regretting that u cud have asked for and all that.....the time is now!!!! stay strong!!!!
THANKS to goiit for giving a wonderful platform to discuss and learn the intricacies of science!!!! m really grateful to this site.....
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yes u r....no probs for u!!!!
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dont panic....its just 5 days for results....prepare well for other exams!!!!
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111 stands little chance in general category....though u r on the boundary!!!!
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it will be interesting to comment on current density here....guess it will clear ur concepts more!!!!
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i hope this helps.....first it all depends upon how u define "easily".....note that u asked current not the current density...(J=I/A)
consider two wires of same material and cross section A1 and A2 (A1>A2)......connected to same source..... flow of current is due to the electric field created due to potential diff of source.....now V=IR....
for same source V is const.... now when A1 is connected the no of atoms cut by cross section increases....so as the no.of free electrons...now the electric field created will be same in A1 and A2 because epsilon will be same(due to same material of conductor).....so the no.of electrons motivated to flow at A1 will be greater,,,.REMEMBER-the field will be same in both the cases.....hence the "current" will be greater in A1....this is the reason for const called resistance to be smaller than A2..... hope it helps!!! all d best....
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write d eqn of line between 2,4 and 4,5....comes out to be y-x=1.....write d eqn of line perpendicular to it....thats y+x=#.....compute # by satisfying the midpoint of 4,5 and 2,3....3,4....i.e. y+x=7.....then put the values of 0,0 in image formula.....u'll get d desired answer
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and FYI time is hugely dependent on gravitational fields....... for more info. read general relativity.......
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i don't know how u r relating a dimension with its dependence on any other function..............and yes time is a dimension and still we don't know how many more dimensions are there to explain Universe......
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In order that a substance can conduct an electric current, the electrical charge has to be able to move through the substance by means of charged particles. In metals, even when they are solid, the metal atoms split into ions and free electrons. These free electrons can move from atom to atom (or, more accurately ion to ion). Therefore, the electrical charge can be carried on these free moving electrons and the metal conducts the electricity.In solid sodium hydoxide, however, there are no free moving charged particles and so solid sodium hydroxide does not conduct. Add water, however, and the sodium hydroxide dissolves to form a solution. In the solution the sodium hydroxide splits into ions - positive sodium ions (Na+) and negative hydroxide ions (OH-) that are free to move about the solution. Therefore the electrical charge can be carried on these free moving particles and so the solution (but not the solid) conducts
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plz be more specific to ur ques......as far as classical physics is concerned the above answer is correct......
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The solid Earth has a negative charge of about a half million coulombs. The atmosphere has a roughly equal and opposite charge, so that the Earth as a whole is roughly neutral. The charge difference produces a "fair weather electric field" in the lower atmosphere averaging about 6 volts per meter -- however, this field varies strongly with altitude, and is nearly 100 volts per meter at ground level. The total voltage difference between the ground charge and the atmosphere's charge (which exists roughly 30-50 km up) is about 300,000 volts. A simple calculation shows that the total energy stored in the fair weather electric field is 150 billion joules.Since air isn't a perfect insulator, electrons leak from ground to air constantly, trying to reduce the charge difference to zero. This current amounts to 2000 amps. (Easy exercise for the reader: what's the resistance of the atmosphere?) Another simple calculation shows that the electrical power dissipated is 600 megawatts. This is the output of a large electrical power plant. While it's theoretically possible to harness this power for use by people, the fact that it's spread throughout the entire globe (to the tune of about a watt per square kilometer) makes it impossible in practice.Since charge is constantly leaking between ground and air, there must be an "electrical generator" somewhere which is pumping electrons from air to ground, against the electric field. Thunderstorms are the generators. The movement of air and charged cloud particles within them separates electrical charges vertically; lightning then transfers the extra electrons at the base of the cloud to the ground. Positive charge at the top of the cloud leaks into the upper atmosphere. This recharges the fair weather electric field.
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answer for u- The 'classical' picture of atmospheric electricity is that the Earth as a whole is neutral, but that thunderstorms maintain a voltage of around +300kV at the electrosphere with respect to the Earth's surface, with a current of around 1 kA slowly discharging around 500 kC of total charge separation. The solar wind is supposed to neutralise any net charge that might be there between the Earth as a whole and the solar wind.
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director circle is a "curve" not a circle.......it is the curve where two tangents from another curve are always perpendicular.............in circle and ellipse it is a circle while in other conics it is st. line.......
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now SN1 is much faster reaction hence 3-bromo must be more reactive with this logic.......
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Vriti Edustore
