solve p.bahadur

u'll find dem

a buk must 4 organic has a very gud description abt da topics

 

let da roots b a,b,c,d

a+b+c+d=-4

square on both sides and after simplification u get a²+b²+c²+d²=8

a,b,c,d cannot be natural numbers 8 cant b written as sum of 4 squares satisfying da given conditions

den roots cant be fractions i v carefully inspect da given data

so der must b atleast one complex number as root.but as complex roots exist in pairs der shud be 2 complex roots.

so der r 2 real roots

 

sorry 4 doing a lot of guess work

probably da only way is 2 find out centre of mass by da 4ula it comes 2 be d/3 which is da ans

(m/2+m/8+m/32+_ _ _)d/(m+m/2+m/4_ _ _)

where both numerator nd denominator r in gp

so d_cm=d/3

bg=1/3ab

u can post only one q at a time

i'm solvin 1st q

letz solve dis by elimination of options

substitute x=1-y in da parabola

solve da quadratic in y u have 2 get a positive soln and a negative soln if u substitute the value of a frm options.a&b cant be possible.

so 4 c u get 2 values one positive and negative

and by goemetry u can get da the 2 chords r latus rectum and a perpendicular 2 da given line

so da length of latus rectum must be 4

hope i'm right

sir i didnt get thru iit dis year

i got some 11000 in aieee

i'm thinking to repeat da exam next year but my parents r hesitatin a bit

dey r trying 2 join me in a state college as i got a good rank in eamcet

can u pls help me out of here