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Acceleration is maximum at a point where radius of curvature is minimum. Since accn= V^2/r , at point  B radius of curvature is minimum, answer is   (2)

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mgh=0.5Iw^2 where I=7mR^2/2 Now find w
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Let  U1 is minimum coefficient of friction required to keep the car in circular motion of radius r; hence

U1mg=mV^2/r

U1= V^2/rg

Let U2 is minimum o efficient of friction required to stop the car when break is applied:

0=V^2 -2(U2)gr

U2=V^2/2rg

Since co efficient of required friction in second case is just half of first care, Hence car should apply break to avoid the wall

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where  = Relative acceleration of stone with respect to lift

where d= 2 m

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g/11

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g/11

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Oh dear I have gone crazy, Ans is A

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Take Gaussian Surface just inside the Cavity, apply  , Since total charge Q surrounded by the surface is Zero, hence E=0

Ans    B

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You are absolutely right, really I forgot this fact.

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Note if two pieces are joine togather, the samller one elongates first , and wil take full load till it becomes 40cm long , but after getting elongation of 6 cm it will come in equilibrium, hence no further elongation. Hence elongation is still 6 cm

Ans is 6 cm

 Discussion Forums -> This Post 0 points    (0    in 0 votes )   [?]

Note if two pieces are joine togather, the samller one elongates first , and wil take full load till it becomes 40cm long , but after getting elongation of 6 cm it will come in equilibrium, hence no further elongation. Hence elongation is still 6 cm

Ans is 6 cm

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ITS INDEED IN TERMS OF POTENTIAL ENERGY CHANGE

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This much joule of heat is generated

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Average force= Area under the given curve/ total time T

Force

Now if anyone to involve F in the result then it can be manulated by substituting T/2 = F

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Relative velocity of ball in y-direction(Vertically upward):

Relative acceleration of ball in y-diection(Vertically downward):

Applying

but relative height covered by ball is Zero i.e.   h=0

Hence

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From FBD of block:

.................................(1)

...............................(2)

From FBD of wedge:

..............................................(3)

Solving for a12

Length of the wedge surface

For minimum Vo, block should stop at L

Substituting V12, L and a12 we get:

NOTE: I AM QUITE SURE ANSWER CAN NOT BE IDEPENDENT OF ANGLE OF T HE WEDGE

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Let us make a few assumptions before solving the problem as stated below:

1. After collision the block moves along the surface of wedge with respect to it.

2. The wedge moves in horizontal direction.

Let us assume x-aixis along the surface of wedge and y-axis along normal to the surface of wedge.

From FBD of block:

Applying conservation of momentum along x-axis:

....................................(1)

Along y-axis:

....................................(2)

From FBD of wedge:

.........................................................................(3)

Solving above equations for V12 we get

:

Once relative velocity of block with respect to wedge is found at t=0, now we will try to find Relative acceleration of block wrt wedge.

See next part of solution.

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