Messages posted by KAB

Karthik2007 has given the correct answer.
Here is the explanation,
de-Broglie wavelength at absolute temperature T is

=h/

(3mkT) Where k is Boltzmann constant.

At 927 degree celcius,

=h/

(3mk(1200))

At 27 degree celcius,

₁=h/

(3mk(300))

So

₁=2

Check this site for last year opening and closing ranks for NITs http://ccb.nic.in/OrCr06/eng/orcr.htm

You will surely get in NIT Surathkal.
Last year for a state rank of 232 Chemical,Civil,mining and metallurgy were available.Check this site for more details http://www.nitk.ac.in/index.php?option=com_content&task=blogcategory&id=143&Itemid=116

I feel IT in DCE is better but the final decision is left to you.

DAIICT is a good college.Check their website for more details.

Sorry to say that you are not eligible.Study well in future.All the best.

Yes rajat,your estimation is correct.Check the aieee website for opening and closing ranks of AIEEE 2006 for estimating still accurately.

Sankydreams has given you some good advice.You must make a proper time table and decide how much time you should devote to physics, chemistry and maths and stick to the time table without fail.
First you must clearly study the theory and the worked examples.If you have any doubts get it cleared and then move on to exercise problems.Once you are clear with basics you can cope up with the ongoing syllabus easily.

Best of luck!

Last year mining was available at NIT Surathkal for state rank of 350(KAR) at the end of first counselling.You may get other branch after second counselling.

Check this site for opening and closing ranks for AIEEE 2006 http://ccb.nic.in/OrCr06/Stream.htm

We cannot exactly predict how it will vary this year.

Hii.....since you love science you can easily learn the exam portions and master them.

Now you have just entered class 11 so first read the theory part properly.When you are confident that you can answer all types of questions from theory part, move on to solve problems.

First clearly study worked examples.Understand them properly.Then move onto simple problems from exercise.If you couldnt solve some go back to worked examples and study again.Keep repeating this until you have solved all the simples problems from exercise.Once you have finished it go for the tougher ones.Remember that a single problem can be solved in many ways.So choose the best and shortest method.

Problem solving technique can be mastered only by practice.Now you have a lot of time to practice.So please dont give up preparing for IIT.

Once you get the problem solving technique then you will be among the best in your class.

ALL THE BEST..

Given ylogxlogydx+dy=0

So ylogxlogy= -dy/dx

or dy/(ylogy)= -dxlogx

Now integrating this we get,

log(logy)= -(xlogx-x)+c

So the general solution is x-xlogx-log(logy)+c=0

Q1)The concept to be applied is the initial potential energy of the spring and the gravitational potential energy of the block gets converted into heat and the water and the block absorbs that heat.

Since the block is suspended completely in water we should calculate its apparent weight.

Volume of the block V=1.2/6000=0.0002m³

Weight of the water of same volume=0.0002*1000*10=2N

So apparent weight of the block is 12-2=10N

To calculate potential energy of the spring:

We know mg=kx (Since the spring gets extended due its APPARENT weight)

ie 10=200x

So x=0.05m

So potential energy of spring E₁=kx²/2=0.25J

Gravitional potential energy E₂=mgh=10*0.4=4J

So total initial energy=4.25J

This energy is converted into heat and it is absorbed by water as well as the block.

So using Q=mC

we get

4.25=1.2*250*

+0.26*4200*

So

=0.003⁰C

Given g is the inverse function of f.

So g(x)=f ^-1(x)

or f(g(x))=x

Now differentiate this wrt x.

ie f '(g(x)) g '(x)=1...................(1)

It is also given that f '(x)=1/(1+x⁵)

So f '(g(x))=1/(1+(g(x))⁵)

Substituing this in (1) we get,

g '(x)/(1+(g(x))⁵)=1

or g '(x)=1+(g(x))⁵

In most of the exams they give full marks for those questions for all students.Whether they attempt that question or not they will give full marks(Some may not attempt because of negative marking.)

Mostly they have given full marks this year too.

The answer is B) Zero pressure

Any liquid boils when its vapour pressure becomes equal to atmospheric pressure.So when the atmospheric pressure is zero the liquid immediately boils and hence cannot exist in liquid state.

Given 2cosA=x+1/x

So x²-2xcosA+1=0

So x=cosA

isinA where i=

-1

Let us consider x=cosA+isinA=cisA

So x³=cos3A+isin3A=cis3A (From De Moivre's theorem)

and 1/x³=cis(-3A)

So x³+1/x³=cos3A+isin3A+cos(-3A)+isin(-3A)

=2cos3A

Similarly we can show that xⁿ+1/xⁿ=2cosnA

Hey joy.....who do u think we r?????Do u think we have some special intelligence???????There r so many many many intelligent students all over India who r not the members of goiit...Its true that the performance of that day matters.......If u do well these 2 years and cudnt do well in the exam then all will be in vain.

And one more thing....I didnt write IITJEE2007 at all(Check date and time of this post if u want proof http://www.goiit.com/posts/list/electricity-max-force-8067.htm#44559) well there r many reasons but the main reason is I UNDERESTIMATED MYSELF!!!!!

My AIEEE score is 264 AIR 2302 and state rank(Karnataka) 32

I agree with Himanshu.Now concentrate on your studies and plz stop posting such IRRELEVANT things in future!!!!!!!

Yes yaar my frnd is getting 259 and his AIR is 2746(Roll no. 23701305)

Really well explained yaar...and good effort!

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