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THANKS.

CAN ANYONE PLEASE EXPLAIN ME THE CONCEPT OF STABLE AND UNSTABLE EQUILIBRIUM.

FOR EXAMPLE WHY WHEN =0, THERE IS stable equilibrium. AND FOR =180⁰, THERE IS unstable equilibrium.

NICE BUT PLEASE IMPROVE IMAGE QUALITY.

POTENTIAL IS DEFINED AS V= - .IF IT IS MENTIONED THAT THE POTENTIAL IS ZERO FROM A TO B.ONLY THEN WE CAN CONLUDE THAT ELECTRIC FIELD IS ZERO..

TALKING ABOUT THE MAGNITUDE IT IS 2.304*10^-24.ELSE I THINK ANSWER SHOULD BE -2.304*10^-24 .WE CAN TAKE ONE CHARGE TO BE +1.6*10^-19 C AND OTHER TO BE -1.6*10^-19 C.

HEY GRAB HOLD OF THIS FORMULA

COS(A).COS(2A).COS(4A)....COS(2^n-1A)=(SIN2^nA)/2^nSIN(A)

CONSIDER THE CUBE AS SHOWN AND A CHARGE AT ITS CORNER..TO COMPLETE THE GAUSSIAN SURFACE YOU NEED SEVEN MORE CUBES.THUS THE NET FLUX THROUGH WACH CUBE WILL BE Q/8.

(NOW IMAGINE BIG CUBICAL ROOM AT THE CORNER OF WHICH IS PLACED A LIGHT SOURCE(IN OUR CASE ITS Q/8)).CLEARLY THE LIGHT CANT PASS PARALLEL WAYS SO IT WILL PASS THROUGH THE THREE OPPOSITE FACES.HENCE THE TOTAL FLUX IN OUR CASE WILL BE DIVIDED BY THREE.IE.Q/24.

WELL,

RECHECKING=RETOTALLING

FEW IDEAL REMEDIES ARE -
-> A COPY MUST BE CHECKED BY MORE THAN ONE TEACHERS.

->THERE SHOULD BE A LIMIT TO THE NO. OF COPIES CHECKED BY A TEACHER .

->THE SUPERVISERS MUST KEEP A CHECK ON EACH AND EVERY TEACHER ON HOW MUCH COPIES HE/SHE HAS CHECKED ETC.

AN IDEAL SYSTEM OF EDUCATION IS THAT IN WHICH EMPHASIS IS LAID ON THE CONTENT AND KNOWLEDGE INSTEAD OF THE PRESENTATION.

WELL TO TELL THE TRUTH ,IT WILL DEPEND ON THE TYPE TEACHERS,THEIR MOOD ETC.

THE ONLY THING IN YOUR HAND IS A GOOD WRITING,AND IMAGINATION POWER.

I DO NOT LIKE THIS SYSTEM,SERIOUSLY.

//angle conversion
#include
#include
#include
float main()
{
clrscr();
int p=0;
float degree1,degree2,rad1a,rad1b,rad2;
while(p!=1)
{
cout<<"enter the angle in degree\n";
cin>>degree1;
rad1a=((degree1*22)/7)/180;
rad1b=degree1/180;
cout<<"angle in radians is\n"<cout<<"enter the angle in radians\n";
cin>>rad2;
degree2=(rad2*180*7)/22;
cout<<"angle in degree is\n"<cout<<"enter 1 to quit or any other key to continue";
cin>>p;
if(p==1);
p==1;
}
getch();
return 0;
}

//accuracy required
//program to find tan,sine or cosine of a given angle.
#include<iostream.h>
#include<conio.h>
#include<math.h>
int main()
{
long double angle,p;
int r;
clrscr();
cout<<"enter any angle in degrees ";
cin>>angle;
angle=(((angle*22)/7)/180);
cout<<"enter 1 to find sin of angle ";
cout<<"enter 2 to find cos of angle ";
cout<<"enter 3 to find tan of angle ";
cin>>r;
switch (r)
{
case 1:p=sin(angle);cout<<" the sine of "<<angle<<" radians is "<<p;break;
case 2:p=cos(angle);cout<<" the cosine of "<<angle<<" radians is "<<p;break;
case 3:p=tan(angle);cout<<" the tangent of"<<angle<<" radians is "<<p;break;

}
getch();
return 0;
}

A driver in a car moves with a velocity v .Suddenly he sees a broad wall.

Should he apply the brakes or turn sharply?

edited.

why cant we go like this->
1st man has n choices,
2nd man has n-1 choices and so on
ie.
(n)(n-1)(n-2).......(n-m+1)

please explain.