there will be no councelling (officially) for ranks higher than 6000.. but one may expect this to go as far as 7000 (maybe not even this far) since many people will not go for councelling.

hoffman elimination is also there in the same chapter.

let me tell u that it is quite difficult to explain the whole thing thru a post like this.. instead i can tell you to read about saytzeff's rule in the ncert chemistry text books which are available online free download. just search on google for ncert books and you can get them.. read the chapter on alkenes. it is written very well im sure u will have no roblems..

if you still have doubts then surely i will help in a better way.. but first u shud give it a try yourself.

since the duration of the impulse is not given (it generally is not given in such problems) we assume that the impulse is for almost zero time.. otherwise it is impossible to solve this question.

look man.. its cool if you are really tring to help whoever is asking the doubts.. but dont argue when you are wrong.. you know well that as soon as the impulse is given, it will TRY to translaet, but the friction will INSTANTLY make it roll and slip.

now i will ask you politely to stop saying nonsense. dont think that whatever you say is right. i dont blame you for trying to prove yourself, but please get your concepts clear before you argue.

goiit is not made for people who want to act cool and stylish.. its to help students. i really congratulate you if you are in the 8th standard.. but if you are not.. then you are fooling only yourself.

if you really are in the 8th standard , i respect you for trying.. if you can do so much at this age.. then you can be  AIR 1.

whoops.. what a silly mistake.. well take the rate anyway.. lol.. spidey is right!!

bloody hell..

tks spidey.

ok  firstly try drawing rough graph

lim x tend to 0..

RHL = [ h sinh ] = 0

LHL = [ -h sin( - h) ] = 0

so it is continuous at 0.

by inspection we see that it is continuous in (-1,1)

check at x = 1

LHL = [ (1 + h) sin(h + 1) ] = [-(1 + h) sinh] =-1

RHL = [(1 -h) sin(1 -h)]  =  [(1 - h) sinh ] = 0 

so it is discontinuos at x = 1

ashish is right

i think they are all periodic.. abt the 2nd one.. i dont think it is possible to find fundamental period.

the fact is that bw any 2 rational nos you will have an irrational numb., and vice versa.

so altho it seems periodic.. it is not possible to find FUNDAMENTAL period, but any other perid is simple to find.. eg all integers are periods.

pooja this is amazing if u got this far yourself!!

nope.. i was hoping for something on absorption or emission spectra..

anyway cutepooja seems to be saying something else.. the explanation i gave is more concerned with emission spectra... although it is applicable to this case also.. but lets see pooja seems to be giving a more appropriate soln.

hey come on i already solved it!!!

now unless u give it a shot yourself youre not going to move forward man!!

get out some paper and write down whatever i wrote and read it slowly.

everything except the last bit of working is given!!!

try it again and see if you get it.

dont give up and NEVER try to be spoonfed. i will write it fully again if u still dont get it.. but atlest give it a full try first. just redaing willl not help.

o ya n the quantum theory.. well, the electron wud not go from n = 3 to n =2 to n =1 unless these quantum states existed in the first place... i agree the statement is slightly vague.. probably they are mentioning in context to something they wrote before this also?