spilt it frm -1 to 0 and then 0 to 1

and int

f inverse = (1-x)^1/2+1

itz constnt .......

itz cosntnt fuction and equals 4

correct me if m wrng

ya d second one

apply

lim(h-->>0) [f(1+h)-f(1)]/(h)

use this u'll get d answer

cos u get sin[1/h] ...................in one part and sin[-1/h] in other so their grtst integer  r diff

thus lhl=!rhl

is it equilateral ??

spilt them as

sinx/(cos^2x+(1-cos^2x)^2)  +   cosx/[(1-sin^2x)+sin^4x]

nnw for d first one put cosx=t ......................................and fro d second put sinx=v

solve indiviually then combine

u'll get a fourth degree wich u can easily convert to second deree (quadratic)

one q for u :

y we assume 1amu =1.6*10^(-27) kg

in d same way as we need sumthing ............as base so taht we may compare it widothers that's y

we take inductive effct of H as zero so dat we may derive d inductive effct of others incomparison wid it

correct me if m wrng !

 4 sumone

Na Hai Yeh Pana

Na Khona Hi Hai

Tera Na Hona Jane

Kyun Hona Hi Hai



Tum Se Hi Din Hota Hai

Surmaiye Shaam Aati

Tumse Hi Tumse Hi



Har Ghadi Saans Aati Hai

Zindagi Kehlati Hai

Tumse Hi Tumse Hi



Na Hai Yeh Pana

Na Khona Hi Hai

Tera Na Hona Jane

Kyun Hona Hi Hai



Aankhon Mein Ankhne Teri

Bahoon Mein Baahein Teri

Mera Na Mujhe Mein Kuch Raha Hua Kya

Baaton Mein Baatein Teri

Raatein Saugatein Teri

Kyun Tera Sab Yeh Ho Gaya

Hua Kya

Mein Kahin Bhi Jata Hoon

Tumse Hi Mil Jata Hoon

Tumse Hi Tumse Hi



Shoor Mein Khamoshi Hai

Thodi Se Behoshi Hai

Tum Se Hi Tum Se Hi



Aadha Sa Wada Kabhi

Aadhe Se Jayada Kabhi

Jee Chahe Karlu Is Trah Wafa Ka

Chode Na Chote Kabhi

Tode Na Tute Kabhi

Jo Dhaga Tumse Jud Gaya Wafa Ka



Mein Tera Sharmaya Hoon

Jo Mein Ban Paya Hoon

Tumse Hi Tumse Hi

Raste Miljate Hai

Manzile Miljati Hai

Tumse Hi Tumse Hi



Na Hai Yeh Pana

Na Khona Hi Hai

Tera Na Hona Jane

Kyun Hona Hi Hai

ma fav song since long .......   :)

distance betwn their centers =mod(diff bewtn their radii)

write (sin^8x-cos^8x) as

(sin^4x+cos^4x)(sin^4x-cos^4x)

= [(sin^2x+cos^2x)^2 - 2cos^2x* sin^2x] (sin^2x-cos^2x)

=[1-2sin^2x*cos^2x](sin^2x-cos^2x)

nw ur int bcums

(1-2sin^2x*cos^2x)(sin^2x-cos^2x)/(1-2sin^2x*cos^2x)

=(-cos2x)

hope u knw 2 int this

!

for adiabatic change

TV^(gamma-1)=constnt

thus

(T/T2)=(V2/V1)^(gamma-1)

gamma for monoatomic gas is 5/3)

thus

u get T2   answer is

a

write all d compounds wid colours on a paper

then try 2 write or say seprate dcolous wid compounds means all red 2gether all blue 2gether

in thhis way u write them 2 tyms then try wirtin more

belive me m tryin d same

aab tak aadha inorganic hua hai

i gt 142 diff compound     

m gettin d answer as 45

 middle digit             sum                    nos

1                                2                           (1,1) (2,0)        ----- 2

2                               4                            (4,0)(3,1)(3,1)(2,2)-------4

3                                                               --------6

4                                     ------------------------------------8

5---------------------------------------------------------------------9

6                         -------------------------------7

7            ----------------------------------------5

8          ----------------------------------------3

9                      ---------------------------1

 addin them u get 45

m gettin

A=60

B=185

C= 286

D=72