| Message |
|
|
|
co+ will be the answer.........see bond lengt will be inversely proportional to bond strength....here all comds have triple bonds but in co and co+ dissimilar elements are there so electrons will be pulled towards the more electro-ve element and hence decrease the bond strenght and as c0+ has + charge so electrons will still be pulled more and hence it will have the least bond length
|
|
|
|
i am getting the answer for the first ques as 26 and 24 resp.......
let z=x = iy
then the eq becomes
(x-3)^2 + (y-4)^2 = 1
the max dist and min dist of a point from origin which is modz will be along the normal. dist of centre frm origin-25
max=25 + 1= 26(point will be on the circumference
and min. = 24
draw a figure to see clearly......
|
|
|
|
mine.......
aieee.........<500
jee............<2000
|
|
|
|
well the answer is ch3-ch2-I...........IN DETERMINING THE BOILING POINTS, IT IS THE VANDERWAAL FORCES THAT WE CONSIDE AND NOT THE C-X BOND STRENGTH....
The large increase in number of electrons by the time you get to the iodide completely outweighs the loss of any permanent dipoles in the molecules.
|
|
|
|
|
nope...its resonance>hyperconjugation>inductive effect
|
|
|
|
|
|
can u tell me how covalent bonds are stronger than ionic bonds
|
|
|
|
|
ch3-ch2-I............boiling point depends on vander waals forces of attraction and more the mol wt more the vander waals forces of attraction
|
|
|
|
|
super cooooooooooool!!!!!!!!!!!!!!!!!!!!!!.................i loved it..............time to kick some profs asses
|
|
|
|
y = 1 + sinx/1-sinx^2 = 1 + secxtanx
the derivative = secx^3 + secxtanx^2
which is positive for -pi/2 to pi/2
therfore lowest value at -pi/2 and max at pi/2
the range = (-infinity,infinity)
|
|
|
|
|
i am a delhi student,,,,,,,,could anyone tell me at what rank in aieee i can get iiit allahabad,nit warangal,surathkal or trichy?????
|
|
|
|
|
it was good.......pretty good level.........
|
|
|
|
|
by post........haven't got it yet
|
|
|
|
|
well one way is to do the questions last to first..........the difficcult ones will take time but will make u adept....
|
|
|
|
|
because if the salt is formed then the product will have the +ve charge on nitrogen which will be highly unstable.
|
|
|
|
