Ø
+ C = C
O==C---C---CH3 < / \
| | C C
CH3 CH3 \ + /
C
COMPOUND 1 COMPOUND2
ITS GIVEN THAT COMPOUND2 IS MORE STABLE THAN ONE .
STABILISING FACTORS IN COMPOUND TWO INCLUDE HYPERCONJUGATION BY 4 ALPHA HYDROGENS
AND THE DOUBLE BOND SO FORMED IS IN CONJUGATION WITH C=C SO RESONANCE .
IN COMPOUND ONE THERE ARE SIX ALPHA HYDROGENS PLUS THE DOUBLE BOND IS IN CONJUGATION WITH C=O MAKING RESONANCE POSSIBLE AND INCREASING CLOUD DENSITY AROUND O SO ISNT COMPOUND 1 MORE STABLE THAN 2 ??
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MY COACHING MODULE SAYS PHENYL FREE RADICAL IS LESS STABLE THAN METHYL FREE RADICAL . BUT IN PHENYL FREE RADICAL DON’T U HAVE AROMATICITY ?? SO WHAT MAKES METHYL FREE RADICAL MORE STABLE ??
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WHICH OF THE TAUTOMERIC FORM IS MORE STABLE ??
C –OH
// \
C C
| ||
HO-- C C—OH
\\ /
C
OR
C ==O
/ \
C C
| |
O== C C==O
\ /
C
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LASTLY, A COMPOUND HAVING HIGHER DIPOLE MOMMENT IS MORE STABLE OR THAT WITH NO DIPOLE MOMMENT IS STABLE . I WAS UNDER THE IMPRESSION THAT IF DIPOLE MOMMENT EXISTS THEN MOLECULES HAVE DIPOLE DIPOLE INTERACTIONS WHICH ACTUALLY STABILISES THE SYSTEM . BUT I SEE THAT MY TEACHERS SAY TRANS IS MORE STABLE ???????????