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dear your question is not complete. bt i knw that this is rorkee 1992 problem.

H₂S--------> H⁺ + HS^- K_a1= 10^-7

HS---------> H⁺ + S^2- K_a2 =1.3 x10^-13

HCl----> H⁺ + Cl^-

now due to common ion effect the dissociation of H₂S is suppressed and the [H⁺] in the solution is due to HCl

K_a1 = [H⁺][HS^-]

---------------

[H₂S]

10^-7 =[0.3][HS^-]/[0.1]

Therefore [HS^-]= 3.3 x10^-8 M

Ka₂ =[H⁺] [S^2-]/[HS^-]

K_a1 x K_a2=[H⁺]²[S²]/[H₂S]

Placing Ka1 and Ka2 in the obove expression we get [S^2-] as 1.4x10^-20 M

ans ) fst ans is benzaldehyde1705cm- is a peak for C=O stretch.

2820 and 2710 is aldehydic C-H stretch doublet due to fermi resonance.

above 3000 aromatic C-H stretch

refer spectroscopy by ps kalsi or ELIEL.

well this is not a part of jee syllabus.

2-bromo anisole ----- NaNH2/NH3------>

it w'll give 2,3 dehydroanisole and then m-anisidine

Q )p-nitrobenzene sulphonic acid is formed fron the reaction of p-nitrobenzene but chlorobenzene will not give benzene sulphonic acid on treatment with NaHSO₃

error:I THINK DEAR ITS NOT P NITROBENZENE ITS p-chloronitrobenzene.

ans) in p-chloronitrobenzene nucleophile displacement of Cl^- by SO₃Na. here the reagent SO₃^2- is a nucleophile , with an unshared pair of electrons on sulphur.

in ordinary sulphonation of , the reagent,SO₃ is an electrophile with electrondeficient sulphur

okie guys i m here for ur help. sorry i took hasty decision.

cheers

Q in optical isomer why asymmetric carbon atom is used and not symmetric ?

Ans) becoz the mirror image of symmetric compound is superimposable becoz they are identical whereas in asymmetric the mirror images is nonsuperimposable becoz they are not identical and exists as enantiomers.

allenes are optically active bt they are devoid of chiral centre.

in allenes the central carbon is sp bonded. the remaining two p orbitals are perpendicular to each other , and each overlaps the p orbital of one adjacent carbon atom forcing the two remaining bonds of each carbon into perpendicular planes therefore the allenes of type ABC=C=ABC(A

B) are chiral.

and thus allenes exist as entiomer without having chiral centre

LE model ? a molecule is composed of atoms that are bound together by sharing

pairs of electrons using the atomic orbitals of the bound atoms

LE model ? a molecule is composed of atoms that are bound together by sharing

a molecule is composed of atoms that are bound together by sharing pairs of electrons using the atomic orbital of bound atoms.

well according to me NH₃ is a strong ligand. and pairing of electron depends upon the pairing energy(P) and CFSE(

). if

is more than P then pairing occurs ie strong field effect.

http://www.goiit.com/posts/list/physical-chemistry-which-of-the-is-a-buffer-50337.htm#254864

look guys we rn't getting monetary favour in helping people here....i jus came here to help people . u can't even imagine what i paid for an hour lecture..bt there are certain elements those who doesn't knw how to respect seniors..

i m sorry bt this is beyond my limits.

this is planar and CN- can attack from above the plane or below the plane givin enantiomers(R and S) so in one CN w'll be above the plane and in other it is below the plane.

where as in acetylene the no of sigma bonds formed by carbon is 2

so the hybridization w'll be sp(s,p,p,p,d,d,d)

for hybridization u have to check the no of sigma bonds.

for example in methane the no of sigma bond is 4

so the hybridization w'll be sp³(s,p,p,p,d,d,d)

now in case of ethene

the no of sigma bonds formed by c is 3 so the hybridization w'll be sp²(s,p,p,p,d,d,d)

the more the s character , the more acidic is the C-H bond.acetylene for instance is more acidic the alkene and alkanes.