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A particle moves with deceleration along a circle of radius so that at any moment its tangential and normal acc. are equal in magnitude.At initial moment t=0 ,the speed of the particle equal to v

Q1.Speed of the particle as a function of time t is given by v(t)=v/k1+k2*v*t/k3*R

please answer

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let 0<x<pi/4 ,then (sec2x-tan2x) equals

my answer is coming tan(pi/4-x) but given answer is tan(x-pi/4)

but answer is 5(5pi-sq.root2)/2

sorry answer is -squareroot(3)/2

but in question it is given A+B-C=pi

Q1. (1+cos(pi/8)(1+cos(3pi/8)(1+cos(5pi/8)(1+cos(7pi/8) is equal to....
Q2. The number of all possible triplets(a,b,c) such that a+bcos2x +csin^2x=0 for all x is......
Q3. The sides of the triangle inscribed in a circle subtend angles A,B,C at the centre.The minimuvalue of the arithmetic mean of cos(A+pi/2), cos(B+pi/2), cos(C+pi/2) is equal to...........

Q4. without using tables prove that sin12sin48sin54=1/8

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Q1. Find the area of the smaller portion of the disc of radius 10 cm cut off by a chord AB which subtends an angle of45/2 degree at the circumfrence.

Q2. given A+B-C=pi ,prove that sin^2A +sin^2B +sin^2C=2sinAsinBsinC

Q3. for all values of A in [0,pi/2] ,show that cos(sinA)>=sin(cosA)

Q4.The larger value of cos(log A) and log(cosA) if e^ -pi/2<A<pi/2 is.............

if cos(A+B)=4/5 and sin(A-B) =5/13,find tan2A if A,B lies between 0 and pi/4

how u get the integral solution as 2

if cot? equals to the integral solution of the inequality 4x^2 -16x +15<0 and sin? equals to the slope of the bisector of the first quadrant, then sin(?+?)sin(?-?) is equal to:

please solve

find the greatest value of f(x) =2 sinx +sin2x on [0, 3pi/2]