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Catalogs Discussion Forums -> Computer Science -> Shreyashji 23 may -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1 replies   
what is that??
Catalogs Discussion Forums -> Counselling Zone -> cannot concentrate in studies -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
4 replies   
give up any kind of cartoons or serials.... get some good books.... play games whenever you feel bored..
Catalogs Discussion Forums -> Inorganic Chemistry -> why is mercury a liquid? -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
12 replies   
Hg belongs to the Zn group...... these are not transition metals....... they don't have strong metallic bonds...
Catalogs Discussion Forums -> About IITs and JEE -> BITS likely to overtake IITs !!! -> Go to message
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76 replies   
simple.... BITS has 4 letters, IIT has 3 letters...... I guess this is what the author was thinking of....
Community shelf Community shelf -> 50 Fun Things to do to Annoy Your Physics Professor -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
14 replies   
is this a joke??
should I laugh?
Catalogs Discussion Forums -> Counselling Zone -> aieee help... -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
13 replies   
I have received mine....
Catalogs Discussion Forums -> Lounge -> HEY FRNS..JUST 4 INSPIRATION...GIVE YOUR IDEAL PERSON N Y. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
27 replies   
My inspiration was Master Lee.... as the record says... he got official recognition for his martial art JKD from the US only when he was about 30....... not just founding an art, but acquired recognition for that in the orthodox United States........
Do I need to say anything more about why he's an inspiration....
Catalogs Discussion Forums -> Lounge -> HEY FRNS..JUST 4 INSPIRATION...GIVE YOUR IDEAL PERSON N Y. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
27 replies   
@ nishant.......
be a bit responsible about your post..... Dr A P J Abdul Kalam is the name of our ex- president, he doesn't have an 'Azad' or whatever next to his name...
Catalogs Discussion Forums -> Differential Calculus -> limits of composite functions -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
6 replies   
About the example... you need to understand the difference between an 'if -then' statement and an 'if and only if' statement....
let me show you something....
you divide 64 by 16....
64/16.. you cancel off the '6' in the numerator and denominator... you get 4/1, hence the answer is 4
same with 95/19, cancel both nines, answer is 5.....
This doesn't mean you can do this everytime... just because this technique works in some cases, you can't generalize this... when you generalize, you need to tell something that holds in all cases... that doesn't mean that there is no case against it...
there are many statements in math which are very true, yet their converse may not always be true...
You need to know more about statements.... try some books
Catalogs Discussion Forums -> Differential Calculus -> limits of composite functions -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
6 replies   
Trace the graphs, you'll understand each part of my above explanation

Coming to what you've asked... about the continuity of 'g'...
the range of 'g' becomes the domain of 'f'... this must be very clear now....
you are concerned about the neighbourhood of x=a.. here, g(x)=m...
If a function is continuous, you can simply take the value of lim as x tends to a as f(a)...
here, take that y=g(x).. replace this y in f(g(x))
it becomes limit as x tends to a, f(g(x)), or lim as x tends to a, f(y)
but as x tends to 'a', g(x) tends to 'm', or simply, y tends to 'm'...
so, we can rewrite that as limit as y tends to m, f(y)
you first go to prove that f is continuous at y=m.. i.e, f is continuous at g(x)=m..... when this is proved, you can simply take limit as y tends to m, f(y) as f(m)......
Catalogs Discussion Forums -> Differential Calculus -> limits of composite functions -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
6 replies   
Starting it all over again......, think about the graphs of the functions....

for a function f(x), if someone asks you to check the continuity, you are only worried about the 'y' values, the output values of the function and check if they are continuous in some given interval, an interval in 'x'... if this is true, you say the function is continuous, and whenever a function is continuous, you can take the limiting value as x tends to some 'a' as f(a)
Whenever the function is not continuous, two cases arise, the limit doesnot exist... i.e, the function has two curves that don't meet, like the step function or the signum function.... or even y=1/x...
else, you can have some function like y=x for all x not equal to 0 and y=1 for x=0.. here, you have a value for the limit, as x tends to 0, yet the function is discontinuous...
Catalogs Discussion Forums -> Differential Calculus -> limits of composite functions -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
6 replies   
I've given a clear hint, you try to think of the exact relation between your question and my answer, if you don't find any, I shall be ready with a reply...
Catalogs Discussion Forums -> Differential Calculus -> limits of composite functions -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
6 replies   
Try to think of a graphical solution...........

take, for example, f(x)=x.x
at x=1, you have the function value as 1, at x=2, it is 4


Now, if you consider f(2x), at x=1, the function value is 4, at x=2, it is 16......

Here, you perform two operations... the domain of the function f is not the region where you consider the values of x, but instead, it's the range of the function contained within f, i.e, the range of (2x) for a given interval for x in my example.....

in your question, the first part..... you are taking the limiting value of the function f..... but it's domain is not a neighbourhood of a, but instead, it's domain is the range of g, when g has the neighbourhood of a as its domain.... I guess you understand me....
as x tends to a, the value of g(x) tends to some other value, which may or maynot be equal to a, in your case, m.
Catalogs Discussion Forums -> Coaching Institutes & Course Material -> How new IITJEE pattern is slowly killing kota? -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
49 replies   
9 students from the same campus in Vijayawada Sri Chaitanya are in the top 100.......
Catalogs Discussion Forums -> Organic Chemistry -> good Conceptual Question -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
3 replies   
It's still a deactivating group.....
The inductive effects dominate the mesomeric effect when it comes to substitution....
 
 
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