goIIT: IIT JEE AIEEE CET WBJEE VITJEE BITSAT IIIT AICET Engineering Entrance Experts, Student Discussion Community, IIT JEE Preparation Online

Ryuamakusa

I think u dint get my approach of doin it

all terms like 1,2007 2,2006 ......... pair up to give multiples of 2008
only 1004^2008 is left which is obviously divisible by 2008

hey allam wat do u maen by pole

The question might be choose the wrong ans

tis is simple

use binomial thm to club the terms that add to 2008 as

X^2008 + 2008-X^2008 = 2008^2008 - other terms of 2008

IS THIS A DOUBT OR A CHALLENGE

NE WAY

1) 8*rt2* a

2) I THINK THIS QUESTION IS INCOMPLETE

3) TRIANGLE TAPQ WITH FOUR VERTICES ???? I DINT GET U

4) a)

1) Well I Didnt get the ans man I think theres more to the que

2) RyuAmakusa
THE CASE IS IS IMPOSSIBLE becos f(0) > 0 and graph cant be continuous with roots btw 1,-1

A B C if l is slant length

Nuksi
The ans which u gave is definitely wrong bcos it eventually bcoms the eq of 2 imaginary lines

Yes it is a combination of rot and shift of axes

eq is 2X^2 - 3Y^2 = 1
Formula for rot of axes is
X= (xcosO - ysinO)
Y= (xsinO + ycosO)
If eq of line is sometin else apply the shift in axes as X+ h and Y +k

h = -3 k = -2 ( lines intersect at 2,3 )

tanO = -1/2 ( slope of transverse)
sinO = -1/rt5 cosO = 2/rt5 ( O in 4th quad)

substitute and get

2 ( 2X + Y - 3)^2 - 3( 2Y - X - 2)^2 = 5

good question

1 for first eq it is in the form of root of a sq
sq my ans and see ull get the exp

2 In the second one sorry I made a mistake
THE ans is 3
Let the exp be X
Cube the exp
X^3 = 12 + 5 X ( try it urself and see)
hence X=3
If u dont get it reply I will ans

3 again wat is - -

AT THE MIDPOINT OF DOOR EDGE

SO THATS THE MISTAKE
IT IS 1.5 FT
THEN THE ANS WILL BE 43N

TORQUE ACTS ON A DIRECTION PERPENDICULAR TO PLANE OF DOOR
MAN THESE ARE BASICS

THE method involved is area of med.triangle = 1/3 ar of triangle

Solve the det to get ans

IS THE ANS 3^29 /2 - 1

yes ans is 10