i think its easy even my chemistry is below standard

nucleophiles are species which attack on the carbon which the base doesnot do

hope u got it.

not getting it man plz elucidate a bit more

@kaymant sir this was when we were talking in a non-relativistic regime now my doubt is that will the ans change when we are in a relativistic regime

I dont think the there would be any change as charge remains constant in a relativistic regime unlike mass.

plz comment.

but friends u all have left the 2nd part that what will happen when the charge Q tends to infinity?

I know that the drop will explode but my confusin is that can we find the no of small drops formed after the explosion

obviously we cannot conserve energy as some energy will be lost as heat,wsound etc.

usually a drop is in spherical shape due to the surface tension but if it is given a charge gradually  then what will be the effect on the shape and size of the drop ?

what will happen if the charge given  Q tends to infinity?

i dont think that its right

i might be wrong  which is the case for 90 % times

write it as integral of sec²x.secx

now put secx=(1+tan²x)^1/2 in the above eqn

now substitute tanx =t

therefore sec²xdx=dt

integral of (1+t²)^1/2dt which is in the standard form and can be easily integrated

hope u got it.

plz give me options i will surely tell u the ans

the eqn reduces toa rather simple exp.

{(sin²x+cos²x)(sin²x-cos²x)(sin⁴x+cos⁴x)}/(1-2sin²xcos²x)

1=(sin²x+cos²x)²=sin⁴x+cos⁴x+2sin²xcos²x

=>   sin⁴x+cos⁴x=1-2sin²xcos²x

now puttin this value in the above eqn we get

integral of  -(cos²x-sin²x)dx=integral of -cos 2x

finally ans= sin2x/2

hope u got it.

in a non-relativistic approx. the Lorentz force does not depend on the choice of the intertial reference frame

F=qE+q(v x B)    the formula is vectorially written

in the frame of the elevator the u r having some vel and the electron is also having some vel so acc to Lorentz expresiion the value of v has changed but the correcponding value of E has also changed in ur frame keeping the net force constant.

actually there is  division  of the force into electrical and magnetic comp.

so i think that there is the transformation of magnetic force into electrostatic force !!!!

tell me if i m correct?

when i told my view on the ques which acc to me is right then y r u going mad abt that it is a rc circuit or not

which eqn u want to apply even if it is a rc circuit ?

but i think that it is not a rc circuit.

tell me if i m correct???????????????

the potential of the 2 plates will be different initially

so a current will flow from higher potential to lower until a state of eqlm is reached when no current flows through the resistor.

when the potential of both the plates will be same then there will be no electric field  as there is no electric field for equipotential surface.

tell me if i m correct????????

some1 plz reply

rates assured for trying also

which of  these field can be circular in shape?

a)electrostatic field                                       b)magnetic field

c)gravitational field                                         d)none