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Kamalasai, you always get away with a "nice..............". lol. hehe ;)
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abhu ma' man, could you please post the idea for solving it too ? Thats the point of being here, right ? Sharing knowledge. :)
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@ nadeemoidu : Good point man. I didn't notice it. Anyway, isn't it integratable ? I can't understand why its not.
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Shubham, its not easy to differentiate these. And what if the answer is the 4th one ? You'll lose a lot of time.
And yo mona, is that you in the picture ? 
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What is this supposed to mean ?
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Could you please post the graph ? Please ... ?
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My answer is :  3 - log3
Please rate if it is correct. :)
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I didn't get it at all :(
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If I solve the whole book of Pradeeps Maths, Pradeeps Physics, Pradeeps Chemistry, can I get a descent rank in AIEEE ?
I know this is kinda awkward but, will it give me descent rank in IIT ?
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It can be integrated (I think). Here's my attempt :
 (cosx-sinx) / (sinx) dx
Let I1= (cosx) / sinx dx
Let I2= (sinx) / sinx dx
Integrating I1
Take sinx = t2 ; cosxdx = 2tdt
I1= 2t/t dt = 2 dt = 2t = 2sinx
Integrating I2
Take sinx = t2 ; cosxdx = 2tdt ; dx = (2tdt) / cosx
I2= (sinx) / sinx dx = 2 (t3) / [t(1-t2)] dt = 2 t2 / (1-t2)
= -4t - log|t-1/t+1| = -4sinx - log|sinx-1/sinx+1| + C
I've skipped some steps here since they are less significant.
Result
I1+I2= 2sinx - 4sinx - log|sinx-1/sinx+1| +C
= -2sinx - log|sinx-1/sinx+1| + C
There it is. Its the answer. I can't understand why its non-integrable. But its just my humble attempt. Someone please confirm it.
If you think its right, please rate me. :)
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Can anyone post a detailed solution for the 1st question ?
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Hmm... seems that it is kinda confusing. Hang on while I ask my tutor about this.
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Is the method you suggested be used in higher degrees ? I mean, in
dx/sin5x+cos5x and all ?
Would appreciate some more explanation.
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Great man. But, could you also include details and dates about AIEEE too ? I'm finding it really difficult to get any info about it.
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