Kh = 4.27 x 10^5

P = 760mm

solubility means mole fraction

we knw dat

p= kH x

x = p/Kh = 760/4.27 x 10^5

u'll get

1.77 x 10^ -3

mass = 10g

molar mass = 122.5 g mol^ -1

calculate molality

calculate alpha by the formula

Ka = C (alpha)^2

after dat calculate vant hoff factor using i= 1+ alpha

and put all the values in

delta T = i Kf m

no of moles of nalorphene in 1Kg of water = 1.5 x 10^ -3

molar mass of nalorphene= 312kg mol^ -1

weight of nalorphene in 1.5 x 10^ -3 mol is = 1.5 x 10^ -3 x 312 = 0.468 g

total mass of solution is 1000.468 g

the solution required for 1.5 x 10^ -3 g of nalorphene is 1000.468/0.468 * 1.5 x 10^ -3 = 3.2 g

the reactions which take place in one step are called elementary reactions.

i dont think it can be determined whether it is an elementary reaction or not....

amt of solute in 25% of 300g  solution - 25% of 300 = 75g

amt of solute in 40% of 400g solution- 40% of 400 = 160g

total amt of solute = 75 + 160 = 235g

total amt of solution = 300 +400 = 700

percentage of solute in this solution =  = 33.5%

percentage of water is 100 - 33.5 =  66.5%

i knw where kv is myself being frm der bt frm the station i dont knw the way!!

yup, anytime after 20th

it is an upcoming field.

its situation is same as that of biotechnology and as far as i knw, its a good field to choose but the thing is u will have to do further studies too and job prospects are more in other countries!!

thanx once again

thank u

:)

nice one......

:D

poor harry though

I think we get an allylic chloride

ie according to ur example it shud be

CH2=CH-CH2-Cl

A wonderful site...........must really thank admin sir for running dis site....not only dat, it requires a lot of grit to run this site.......along wid the day to-day job...not everyone has the patience to do so.......admin sir is an exception, the way he has run the site,..seriuosly hats off to him

:)

this site is more like a coaching institute in itself............the experts are very helpful and even the members are equally helpful

i agree dat this  site is like a family.....

goiit rocks!!

let us all help in keeping it so.......

:)

and yes, @gonik, u have started a gud thread!!

cheers