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dinesh is right .....the ans is 20m
it is 2d motion
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simple..
a)given rate of discharge = 1cc
v1 = rate of discharge/a1 = 1/(4*10^-2) = 100/4 = 25cm/s
b)use eq of continuity
a1v1 = a2v2
1 = 2 *(10^-2) *v2 as a1v1 = rate of discharge
v2 = 100/2 = 50cm/s
c)use bernoulli eq
Pa + (dv1^2)*1/2 = Pb + (dv2^2)*1/2
Pa - Pb = 1/2*d*(v2^2-v1^2)
= 0.5*1000*(2500 - 625)*10^-4
= 93.75N
rate if useful.....
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ans is c
as resultant vector will be close to the vector with greater magnitude i.e the angle between resultant vector and greater magnitude vector is lesser than that between resultant and lower magnitude vector
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|c| must be less than |A-B| as angle between A and B is obtuse and cos of obtuse angle is -ve.
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is it 15s?
if not wats the ans?
plz reply
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sry abt the double post...my bad
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but even if friction does act....work done by friction in pure rolling is 0 so u can always conserve energy
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but even if friction does act....work done by friction in pure rolling is 0 so u can always conserve energy
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