does any websites provide details about branch wise placements in iits?

some one from iit madras student, alumni or faculty do nudge me

it is a sphere

the axis of symmetry passes through its center

MI about that axis is 2/5MR²

 (mass x sum of square of perpendicular semi axis) x  1 /n= M x( R²+R²) x1/5= 2/5MR²

put it as

1/c=k(1/a-1/b)

if b increases 1/c increases bcoz 1/b decreases and hence c decreases

0.5=1/2

log_o.5⁴⁼ -2

use this

[x]+[x+1/n]+[x+2/n]+....+ [x+n-1/n] = [nx]

because r/n<1 for   r<n-1

so  [x+r/n] = [x]

where r<n

hence the result follows

The function [x] gives the integer immediately left of x.

It can also be expressed as x-{x}