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Catalogs Discussion Forums -> Modern Physics -> "ATTENTION" DO YOU KNOW THAT NEIL ARM STRONG HAD NEVER LANDED ON MOON>>>>>>>>>>>>>>>>>>>>> -> Go to message
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well here is the end


   THEY HAVE SHOWN IT MANY TIMES ON DISCOVERY..........AND THE AMERICANS HAVE GIVEN THIS ANSWER


WHIC ENDS EVERY DEBATE


1 :   THE STARS ARE NOT VISIBLE BECAUSE THE RESOLUTION POWER OF THE CAMERA DOESN,T PERMIT IT.......IF YOU STAND UNDER A LAMP POST AND LOOK AT THE SKY.THEN SKY WILL APPEAR STARLESS


BECAUSE THEN YOUR EYES ARE ADJUSTED TO NEARBY DISTANCE RESOLUTION BEACAUSE OF THE POWERFUL STREET LIGHT.


MOREOVER THE CALIFORNIAN OBSERVATORY HAS CHALLENGED THAT ANY PERSON WITH ANY QUERRY SHOULD COME TO THEM ...MOREOVER THEY HAVE SHOWN HOW LASER FROM EARTH REACHES THE PLACE WHERE FIRST MAN LANDED..............

Catalogs Discussion Forums -> Analytical Geometry -> Parabola -> Go to message
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here the 'a' in my ist. line is not a of the eq. but focus of the parta. ie. a=2.
Catalogs Discussion Forums -> Analytical Geometry -> Parabola -> Go to message
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the point t is ( at1t2 ; at1+at2) find the cirumcentre .
the loucs will be such that x= f(t1,t2) and y=f(t1;t2) then use the relation
t1.t2= -a ....................1
t1+t2=-2 ...................2
eliminate all t and get the locus
dont't use relation no. 1 as it will again give you anoher constant .
on using 2 you will get a single variable in the two function fs
now eliminate t1 or t2 as per choice and get the locus
Catalogs Discussion Forums -> Electricity -> FOR FUTURE'S MATHEMATICAL PHYSICISTS : TOUGH ENOUGH -> Go to message
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WELL WE HAVE A NORMAL CIRCUIT THE GREY SHADED ONE IS
THE RESISTANCE AND IT IS CONNECTED BY A NON CONDUCTING ROPES TO LIGHT MASS M . THE DETAIL OF ROPE IS GIVEN ABOVE . THE TOP OF THE RESISTANCE IS CONNECTED AGAIN BY A NON CONDUCTING WIRE TO A CEILING . JUST CALCULATE I AS A FUNCTION OF TIME . THE CLOCK STARTS WHEN EQUILIBRIUM IS REACHED AND ASSUME CURRENT TO CHANGING INSTANTANEOUSLY
Catalogs Discussion Forums -> Differential Calculus -> how to solve equation of the form :- 4x = 1-e-6x -> Go to message
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USE SOFTWARE FOR PLOTTING THE TWO EQUATION AND FIND THE INTERSECTION POINT
Catalogs Discussion Forums -> Electricity -> FOR FUTURE'S MATHEMATICAL PHYSICISTS : TOUGH ENOUGH -> Go to message
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COME ON JUST BEAT THE HELL OUT OF THIS QUESTION
Catalogs Discussion Forums -> Electricity -> MIND BOGGLING -> Go to message
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but why
Catalogs Discussion Forums -> Electricity -> MIND BOGGLING -> Go to message
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WHAT IS THE POTENTIAL DIFFERENCE BETWEEN THE POINT A AND B AND PLEASE DON'T GIVE THIS ANSWER


THE STROONGER CELL IMPOSES ITS V ON OTHER BECAUSE IT DOESN'T OCCUR

Catalogs Discussion Forums -> Organic Chemistry -> please clear my doubts -> Go to message
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Catalogs Discussion Forums -> Organic Chemistry -> please clear my doubts -> Go to message
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POSSIBLE DIAGRAM FOR CO4

Catalogs Discussion Forums -> Organic Chemistry -> please clear my doubts -> Go to message
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NOW THE ONLY WAY TO EXIST IS THE DIAGRAM WHICH I POST BUT THEN DUE TO PEROXIDE LINKAGE THE BDE IS TOO LESS TO PERMIT FREE EXISTANCE
Catalogs Discussion Forums -> Electricity -> FOR FUTURE'S MATHEMATICAL PHYSICISTS : TOUGH ENOUGH -> Go to message
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HERE IS THE DIAGRAM

Catalogs Discussion Forums -> Electricity -> FOR FUTURE'S MATHEMATICAL PHYSICISTS : TOUGH ENOUGH -> Go to message
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CONSIDER THE DIAGRAM POSTED LATER. THE WIRES IN RED ARE PERFECTLY NON-CONDUCTING.


THE DATA NEEDED IS


          WORK OF BATTERY/ CHARGE     =     E


          INITIAL LENGTH OF THE WIRE    =      L


          AREA OF THE WIRE                       =      R


         YOUNG' MODULUS                        =       Y


                   MASS     IS           M         AND g IS KNOWN       .


NEGLECT ANY OTHER EFFECT.


                FIND CURRENT AS A FUNCTION OF TIME ONCE THE WIRE ATTAINS THE EQUILIBRIUM POSITION

Catalogs Discussion Forums -> Differential Calculus -> plzzzz expert solve this -> Go to message
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is the distance algebraic or absolute
Catalogs Discussion Forums -> Thermal Physics -> Please help me in solving this question -> Go to message
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dQ=PdV
dQ/dV = p

dQ=dW
dQ/dW =1
 
 
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