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oh and BTW...the sentence in red shd be "since A is not a scalar matrix, mimimal polynomial can't be of ORDER 1" I missed the word "order" there!! :) :)
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Okay....I've got it...after a late night session I've finally got it!! Here's the solution to my problem: 
It's 2:30 in the night....so I may have made some tiny mistake here or there I've folded the page at the top...it was some rough work......jst ignore it!! Same goes fr the big black box at the top. cheers!! PS Thanks fr the help mathie.....it really helped!!
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As the question states, what is the minimal polynomial of a matrix? Particularly, the minimal polynomial of the matrix |2 -1 1| |-1 2 -1| |1 -1 2| please help!!
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Found this nice question and thought I'd share it with you guys!! ---------------------------------------------------------------------------------------- An airline company knows that 5% of people wh buy tickets don't show up for their flight....consequently they sell 52 tickets for a plane holding 50 people Find probability that there will be a place available for every passenger that shows up.
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I'd say IIIT Hyderabad>NIT Trichy BITS Pilani>IIT Guwahati I say this because 1) IIIT H is a institute dedicated to Computer sciences and its syllabus actually allows U to pursue research in the field on CS from the 1st yr itself!! In most other institutes the scope for research starts only from the second yr or third yr. 2) IIT Guwahati is not a preference for CS students.... I dunno the exact reason, but some say the faculty is not very helpful in CS (unconfirmed)...but whtever the reason, IIT-G is among the last IITs students select when going for CS 3) BITS Pilani and NIT-Trichy have an excellent infrastructure when it comes to CS, and great faculty, as well as some of the finest minds in the country, so I can't really differentiate between the two hope this helps cheers!!
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1)Since A, B and C are all positive (coz of given conditions)...we have a cubic eqn of type Dx^3 - Ax^2 +Bx - C, where A,B,C,D are all positive.... so U can use Descartes' rule of signs
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As per problem we have 100 millimoles of HA (200*0.5) and 60 millimoles of HB (300*0.2)...now after reaction, we have 40 millimole of HA....now simply get the reqd things....hope this helps...cheers!!
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Rimi.....actually I have also gotten in JEE 2009 extended list and am thinking of IISER as an option....my rank is 308 in extended list....so i guess U understand tht I'm not a student of IISER so will not be able to give completely accurate info.....however here's wht I know:
1) Looking at last yrs trends, U have a fair chance of getting into an IISER, atleast one of the less prefered ones like IISER Mohali
2) However all IISER students I've spoken to have advised me to join only if I'm really interested in the pure sciences....don't join iiser if U're ultimate aim is to make a lot of money, join only if U want to get into research.....rate the following in order of importance to U..... Respect,Fame,Money......if U get the same order in which they are given, IISER is the place for U, but if it is the opposite, then IISER will be a waste for U....U'll be better off with an engineering course
3)IISER is by far the best college for pure sciences.....infact they were started with the aim of starting IIT level colleges that stimulate research in Pure sciences, and by all standars they are on line to do so 4)See, it is a fact that many people won't go to IISER simply because there is little scope for pure sciences in India after an MS....U cannot set up U're own research facility (coz of the enormous funds involved) but will have to tie up with some research institute like IISc, BARC,Saha institute etc....as such the opportunities for making loads of money is very low.... Think of all these things and then make U're decision....wishing U make the right choice hope this helps cheers!!
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Actually many methods that can really help U to solve problems are not included specifically in the portion for JEE.......this is true especially in the chapters of electrostatics and electricity....methods such as method of images, maximum power dissipation method, Thevenin and Norton equivalents etc are not mentioned specifically in the JEE syllabus but are generally studied as they can really help U get out of some tricky situations.... My personal opinion is that you should study it esp. because even in the JEE some problems have been asked which can be solved in 3 steps using an unconventional method, but in 10-12 steps using conventional methods, so U can save a lot of time using these methods.... if U want to study this method, U can use http://en.wikipedia.org/wiki/Method_of_image_charges or read through Interactive Physics
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Since objects do not fall through the atmosphere at the same rate, I don't think there can be any general formula for time taken for terminal velocity to be acheived....even if there is, it will be way more advanced than the JEE level.... I may be wrong though.....so I'd really like it if a community expert confirmed my hypothesis.....for more on terminal velocity, read http://exploration.grc.nasa.gov/education/rocket/termvr.html ....cheers!!
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assuming work done=change in KE..... KE just before hitting ground=mgh=3000 i.e F.2=3000 so F=1500 N..... now F=ma, so a=500 m/s^2 .... init velocity = root2gh=root2000.... hence useing v=u+at...ie 0=root2000-500t , solving, we get t=0.09 seconds.... so answer is A!! hope this helps...cheers!!
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let the pt be x,y ....then given locus is (x+1)^2+(y)^2+(x-2)^2+y^2=2(x-1)^2+2y^2........this becomes (x+1)^2+(x-2)^2=2(x-1)^2....i.e x^2+1+2x+x^2+4-4x=2x^2+2-4x.....i.e 2x=-3....i.e x=-3/2 .....Hence the locus is a straight line!!...if anything is wrong its simply a calculation mistake coz I've done this all straight on the PC....cheers!!
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Sir I am pretty sure it is true because EML ranks have also been declared this yrand I myself have met a guy whose EML rank is ~46000!!
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chances of getting a good branch in AIEEE is very low....so go for VIT...believe me, speaking from an outsiders perspective, VIT is a very good institute, a few of my friends who are there are completely satisfied with it.....but sincere advie, don't go for institute over branch, always choose branch over institute....best of luck....cheers!!P.S. I'm NOT in VIT!!
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The admission process involves the following steps: I. During 8th-28th June, 2009, all those candidates permitted to fill choices on the basis of AIEEE-2009 results are required to register ONLINE through Internet. (www.ccb.nic.in) from places of their convenience/near by Admission Centres/Help Centres. II. They can also fill their choices of branches and institutions in their order of preference, any time during this period. III. All the candidates must lock their choices on or before June 28, 2009 by 11.55PM. IV. Seat allotment results will be available on the website www.ccb.nic.in. No individual allotment letters will be sent. The successful candidates have to go to any one of the Designated Admission Centres for remote reporting (for verification of Original certificates and payment of initial fee of Rs. 25,000/-) and take provisional admission.V. All the candidates who have taken provisional admission shall report to the allotted institutes during July 16 - 24, 2009. Source: The Results Page at http://cbseresults.nic.in cheers!!
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eh?? No way he's in merit....must be in the EML....merit goes barely upto 7 or 8 thousand.....EML has been lengthened a lot this time (I've even seen people with a rank of 45000 in EML!!!).....with ranks such as this (~14000 in EML) there is almost no chance for him/her....if his luck is amazingly good, he may get in Indian Institute of Maritime Studies (Merchant Navi), Mumbai.......sorry to say this but the truth is sometimes hard to digest....tell him/her to concentrate on AIEEE results or other entrance results.......hope this helps...cheers!!
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I got in the EML....Atleast tht's better than being in the list of "NOT QUALIFIED"!! cheers!!
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This is the structure of Hydrogen isocyanide (isocyanide because hydrogen is bonded with the N, not with the C) (from wikipedia) (The white atom is H, blue is N and grey is carbon It is represented as  ...as can be seen, it is a zwitterion. It is also called hydroisocyanic acid hope this helps cheers!!
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Vriti Edustore
