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well if u want to derive any kind of expansion u can use macclaurin-taylor series but at this stage it is better to learn certain standard expansions.........if u r still interested then i will tell how its done,its not that difficult actually
The Taylor series of a real or complex function f(x) that is infinitely differentiable in a neighborhood of a real or complex number a, is the power series
f(a) + f'(a)/1! +f''(a)(x-a)^2/2! + and so on
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answer shud be 11e/24
(1+1/x)^1/x=e-e/2x+11e/24x^2........
use this and u shall get the answer
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ymca is a decent college.........top branches have good placements.
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my suggestions-----
physics-hc verma each and every to be solved with proper analysis and thinking
maths---tmh for iit jee
chemistry----ncert for inorganic,p bahadur for physical,morrison boyd(but plzz first ask someone how to use the book).
previous year iit jee questions a must
do this much with sincerity and dedication and no one will stop you frm getting thru jee,
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see mate........its ur life,ur the owner of urself.dnt give a damn to what ppl say.if u r passionate abt something and ur heart will get happiness by going for it then nothing should stop u.one or two years dnt matter in a long life rather it will make u a stronger person,much more determined and mature.
ITS A SIN TO COMPROMISE IN LIFE.
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well i think the answer is b).since x^2-x+1 ia factor of the given cubic eqn and hence the cubic eqn has two complex roots the other root has to be real.let that be -k
then (x+k)(x^2-x+1)=ax^3+bx^2+cx+d
compare the coeff to get the answer
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for the first question answer acc. to me shud be a)..............tell me if i am right,i will post the solution if i am
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gets oxidised by oxalic acid to chlorine
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hell.............i got -1/i+1
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geometric progression one is 4
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yeah u can check by puttin values of n
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