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A particle performing SHM of period T about a point O and it passes through the point P, where OP is x, with velocity 'v' in the direction OP. Show that the time which passes before it returns to P again is (T/ ) x tan-1 (vT/2 x)
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A particle in the xy plane moves accordign to the equation:
r = (i+2j)A cos t
Which of the following statements are true:
1. Motion is straight line
2. Motion is Simple Harmonic
3. Motion is periodic
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Get a hold a grade 10 science textbook. The process of photosynthesis is explained there.
From what I remember, photosynthesis occurs in two phases: light reaction and dark reaction.
I think the light reaction can't occur because you need electron transport chains (or something like that) in this step.
Check the textbook. The answer will be there deinately.
Hope this helps
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Te first part should be easy to understand(that linear velocity decreases due to friction).
To have angular velocity, an external torque must be applied.
This torque will be supplied by friction, having magnitude:
Torque = Force applied due to friction ( mg) x Radius of sphere.
Hope this helps
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You want to measure the pressure exerted by the fluid at the point that's moving out.
That height is measured from the top(the same way as in the derivation of the formula h g)
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Mine's pretty much the same as pratyush, so deleted my answer.
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Mass of trolley+block=3m
Force applied = F
Acceleration = F/(3m)
Considering only the block
Force acting backward= Pseudo force ma= m x F/(3m)
Force acting forward = frictional force (Friction acts forward since in a frictionless surface, the block would move backward) = x m x g
In limiting case
Frictional force = Pseudo force
-->  x m x g = m x F/(3m)
--> x m x g = F/3
--> F = 3 x x m x g
--> F = 3 x 0.5 x 10m --> F = 3/2 mg
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Hey
Can anybody give me a list of important reagents and the processes they're used for?
Thanks a lot
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OK, I'm assuming that 'g' is taken as a constant throughout.
SInce the rocket is starting from rest (since initial velocity isn't mentioned), ' v ' of the rocket after 30s is 10x30= 300 m/s.
Then, it's moving against gravity. Final velocity V is 0.
So, using the eqn. v=u+at where v=V=0;u=v=300;a=-g=-10
t=300/10=30 s.
So, total time is 30 + initial 30 of accelerated motion =60s
Hope this helps
Correct me if I'm wrong.
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Use adiabatic eqns. since the volume is suddenly expanding.
Think about it, the air in the tyre is going from being compressed to suddenly expanded in the instants that follow the tyre burst.
This process is obviously quick, so you have to use adiabatic eqns.
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Lokesh is right.
Strength of an acid is determined by the amount of H+ ions it can lose.
Since H3PO4 is tribasic, it is stronger than H3PO3, which is only dibasic.
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Density of air --> 1.2 kg/m^3
Volume filled = V m^3
Vol is a positive value since air is pumped in the balloon.
Therefore, weight of air filled = V x 1.2
Since Vol is +ve and density is +ve, weight is +ve.
So, w2>w1.
Hope this helps.
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@rakiagrawal
If you approximate pH as 7 every time you get actual pH>7, then strong bases can't exist, since water pH=7, and that's certainly no strong base.
What you're referring to is when we get the pH of acids as greater than 7. But for bases, the pH HAS to be above 7.
Akshay Khare's answer is right.
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The eardrum vibrates, causing the three bones (Hammer, Tongs and Stirrup...don't remember the scientific names) to vibrate, which cause a liquid in the cochlea to vibrate. This vibration frequency is interpreted by the brain, causing us a hear.
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