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its very easy if its a carbon atom just count the no of pi bonds it has
no pi bonds sp3
1 pi bond sp2
2 pi bonds sp
the logic is only that we need pure orbitals for the formation of api bond so the no of pi bonds those many pure orbitals the remaining undergo hybridization
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 = workdone / heat supplied to the system
heat supplied to the system = q(ba) +q(ac)
= nrt/(  -1) + 2nrt ln2
q(cb) is -ve so im not adding it up
the problem is that why did u add up heat given out by the system in cb
and did not add up the heat supplied to the system in ac
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there is no pressure diff so i don't think the mercury level wud rise in the tube
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carboanion already has a negative charge on it
species with less charge are more stable so the groups that reduce its negative charge or dont increase its negative charge make it more stable .in prim its -ve charge increased by less amount as wen compared to in ter and sec is the intermediate one
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can anybody tell me why is the statement 1 wrong
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under an ideal case if we don't consider the recoil of the cannon into consideration
we can write the eqns of motion as x= u/2t
y= u 3/2 -gt2/2 for the first body
for the 2 body x=u/ 2(t-t1)
y=u/ 2(t-t1) -g(t-t1)2/2
wen the bodies collide their co ordinates are equal assume t1 is the time interval between both the bodies and t the time wen they collide
if we have to consider the recoil of the gun then there wud be a change in the position of the gun during the two firings we have to find the change and time taken for that change , friction and other things into consideration
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write down the eqns of motion x1=asin(wt )
x2=a sin(wt+d)
d wud be the phase diff between both the particles
a and w are same for both of them
apply the condition given in the prob for some particular time t u get d=pi
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no doubt the ans is A the books may have the wrong sometimes ur solution is correct acco0rding to me
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raulrag009 can u make it a bit more clear i didnt get the very idea of p= f* vmax
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THE ANS IS 96 hp
p= fv
f1/v1=f2/v2
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THE ANS IS 4 U CAN DO IT BY USING COM
COM OF THE 1 ST CYLINDER ( ALONG THE VERTICAL) =H1/2
III LY 2ND CYLINDER= H2/2
COM OHF THE SYSTEM =(H1/2)ADH1+ (H2/2)AD H2
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ADH1+ ADH2
CONSIDER THE TUBES ARE LINKED THROUGH A TUBE OF NEGLIGIBLE VOLUME THEN THE LIQUID IN THE CYLINDERS GETS SETTLED DOWN AT A CERTAIN HEIGHT SAY X U CAN EVALUATE THAT X = H1+H2
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2
COM OF THE SYS IS H1+H2/4
WORKDONE IS =F.DS
= AD (H1+H2)G (CHANGE IN THE POSITION OF COM)
HENCE THE ANS
HOPE U GOT IT
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Q U W
BA nrt/  -1 nrt/ -1 0
CB -nrt( /-1) -nrt/-1 -nrt
AC 2nrt ln2 0 2nrt ln2
effeciency is given by work done / q +ve ( heat supplied to the system)
so i think q = nrt( 1/-1 + 2ln2)
the ans wud turn up diff in this case can anybody help me out
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it has 2 unsaturation factors so u can have 3 structures
1 two double bonds in the compound
2 one triple bond "
3 a ring and a double bond "
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4x+3O2 --------- 2X2O3
4 MOLES OF X WUD GIVE U 2 MOLES OF X2O3
4=0.36/X X MOL WT OF X--------------------------------1
2=0.56/(2X+48) -------------------------------2
DIVIDE 1 WITH 2 AND SOLVE FOR X
ITS COMING OUT TO BE 43.2
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