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|z-1|=1 is a circle in Argand plane with unit radius and centre (1,0) which touches the y-axis at origin. arg(z) will be different for different points on the circle.
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- Start attempting the question paper only after reading the instructions given on it very carefully.
- While attempting questions, go on segregating them by the A, B, C method A :These questions are from topics that you have prepared well, and you can clearly comprehend the meaning of these questions. You have done questions containing similar concept earlier and you are confident that you will be able to solve these. B :You know you can solve these questions but they are time-consuming, nevertheless you are confident you will be able to crack them when you come back to them. These questions should be attempted in the second round of question attempting, i.e. when you have solved all questions marked with a B. C :You don't know head or tail of these questions and you should not waste time attempting them.
- Attempting to solve all questions in haste increases the chances of error. It is better to solve slightly fewer questions faultlessly.
- Never attempt two questions at the same time. Concentrate on one question at a time.
- Carry out all rough work only in the space given in the paper.
- If you need a diagram to understand questions in say physics or coordinate geometry etc., do make one.
- Use the value of constants given in the paper in solving a numerical. If the value is not mentioned, use the one you remember.
- Give all three subjects equal time - i.e. 50 minutes each for physics, chemistry and mathematics.
- While attempting the answers, do not shade the answer key immediately. Instead, tick your response with a pencil 4 on the answer key.
- Keep marking questions with A, B, C in the first round of solving the paper. All questions should be segregated into one of these three categories. This saves valuable time later.
- Fill out the answer key 30 minutes before final time. Fill out the responses to questions attempted after this directly in the answer key.
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The rate of change of temperature with displacement in a given direction from a given reference point.
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It is unknown, it may have an aptitude test. Currently stick to the basics of your current syllabus.
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Of course you can. But from now onwards you need to be sincere. Study in detail the topics of 12th and take out sometime in parallel to go through the basics of topics of 11th. Make a time table and stick to it.
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Normal forms are ^2}}=0%20\Rightarrow\;%20\;%20\frac{3}{5}x-\frac{4}{5}y+\frac{4}{5}=0)
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The terms of the series are all odd. 184 being even can never be a part of this series.
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Its sexually transmitted disease.
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Refractive index is the ratio of speed of light in vacuum to that in the subject medium. Hence it is a dimensionless quantity and has no unit.
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Connect two resistors in parallel and then connect this combination with three other resistors in series.
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please give details about your querie
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just go through arihant publication book for medical enterance examintaion it has complete details about each subject .
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First of all congratulation. you have to be focused on your further studies work hard so that you can achieve a seat in IIT from where u can chose computer science as your stream and enhance your skills.
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)
+c)
Back substitute y to get the answer
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Its integral is -cosx + c. This is a standard and needs to be remembered.
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In general, electronegativity increases on passing from left to right along a period, and decreases on descending a group. Hence, fluorine is undoubtedly the most electronegative of the elements
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Let x/(x-1)(2x-3) = 3/(2x-3) - 1/(x-1) Its derivative is -6/(2x-3)^2 + 1/(x-1)^2
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=cot^{-1}\left%20(\frac{x(x+1)+1)}{x+1-x}%20\right%20)=cot^{-1}(x+1)-cot^{-1}x)
Now use by parts for arccot : \left%20(%20\frac{d}{dx}cot^{-1}x%20\right%20)dx)
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dx=(x+1)cot^{-1}(x+1)+\frac{1}{2}log((x+1)^2+1))
Subtract these two to get the final answer
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The properties of individual elements and when they combine to form compounds are totally different.
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+%20b^{2}sin^{2}x) sin^{2}x)
If a^2 > b^2 then maximum value occurs at sinx=0 which is a^2 and minimum value occurs at sinx=1 which is b^2. Similarly for b^2 > a^2, max. value is b^2 and min. value is a^2 Therefore maximum value = max(a^2,b^2) and minimum value = min(a^2,b^2)
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