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oh,dear!sucide is never comitted after u tell everybody,its just when u feel helpless n u wanna do it
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since its a very lengthy procedure so i can tell u the method:
figure with all forces:a ladder-its weight acting downwards thru COM,weight of man( downwards),N1(frm vertical wall),N2 from d ground,friction(f)= N2.
since d ladder should be in horizontal n vertical equilibrium,net torque abt any pt. should be zero
mg+Mg=N2..put the values get d answer
put d condition(f=N1) 4 horizontal equilibrium also,u'll get d answer
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if a reaction occurs only if the reaction in that direction is spontaneous,then why does the reaction proceed in both the directions in case of reversible reactions where the reaction is spontaneous in one direction?.........rates assured
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@tka is right the direction of friction is opposite to the direction of relative motion.......the question is not at all clear
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in both the cases friction acts in the upward direction.
when the body is moving down the incline,acceleration is downwards,hence the lowermost point has the tendency to go downwards---friction acts in the upward direction
wen the body is moving up the incline since the torque due to all other forces is zero,that means no forcehas got the tendency to make the body roll,hence a friction force has to act to make the body roll,now 4 the direction,see that acceleration of the body is downwards hence the angular acceleration should be anti clockwise n dat's possible only wen friction acts upwards.................
for the direction of friction always keep 1 thing in mind...try to predict the direction in wich the lowermost point of the body has the tendency to go.....friction acts in opposite direction..........i hope its useful
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please suggest some good books(only the best to be referred plz.)for physical,organic and inorganic.please answer as soon as possible
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please suggest some good books(only the best to be referred plz.)for physical,organic and inorganic.please answer as soon as possible
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it means a=b=c exactly it was none of the options so we just modified one and it matched
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on simplifying
3x^2+bc+ac_ab-bx-cx-ax=0
now since the roots are equal
 =a+b+c/3
also ^2=ab+bc+ac/3
from the above two we get
a^2+b^2+c^2-ab-bc-ac=0
(a-b)^2+(b-c)^2+(c-a)^2=0..........this is a formula no derivation is required
 a-b=0,b-c=0,c-a=0
a=b,b=c,c=a
a=b=c
putting in part b of the given options....a+bw+cw^2
a(1+w+w^2)=a.0=0
hence answer is b
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try to predict the direction of friction acting on the body...if not possible take any direction of frictin and it will come as positive or negative resp.in rolling there is only rolling friction which acts
use the translational eq. F=ma
then use rotational equation... =I
then use the eq....v= r or a=r
note...that first step of friction is only valid when body is on an inclined plane or is sliding....since only rolling friction acts on the body while rolling on aplane surface we neglect it.....
if useful...dont forget to rate
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is it necessary that Q should be in downward direction?bcoz i took it in the first quadrant n that too outwards...so i got the answer..(P+Qsin  )/(mg-Qcos )....plz explain me
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