it may be a problem wid the fan inur CPU...if it aint workin properly the temp increases...n the CPU is made such tht beyond a particular temp it shuts down...so plz chk the fan

the mistake made in previous posts is tht they have failed to take into consideration tht the base(log base) is <1

[log{(x^2-1)/(x^2-3x+2)}]^1/2

(take base as 0.3..i not writing it)

so v have [log{ (x-1)(x+1)/(x-1)(x-2)}]^0.5

cancel x-1 in num n denom...note tht x cannot be 1..ie x-1 cannot be 0..

so v have x+1/x-2 inside the log

now the log has to return a positve value cuz then only u can apply the sq root to it

as base is <1 the num inside the log also has to be <1 so tht overall log value is +ve

so x+1/x-2<1  => 3/x-2 <0 => x<2 (but x not =1)

also x+1/x-2 >0(as inside log num shud be positive)

so from this u get x>2 or x<-1 but from 1st statement v got x<2

so answer is x<-1 or x belongs to (-infinity,-1)

@ akku...for n=0 the lim is 0...but the q states tht the lim shud be a non-zero value

0/0 form ..so use L'Hosp...if u diff once or twiceor thrice u stlill get a 0/0 form

on 4th diff u get:

{8cos2x  -cosx + 4cosx*e^x + e^x}/n*n-1*n-2*n-3*x^n-4

numerator is non 0 hence denom shud be non 0 hence n-4=0 so n=4

@ bhattji n=2 doesn work...

cud u define it?

the formula is pretty easy to derive..

jus consider rings such tht number of turns/unit length is n then is length dx u will have num of turns =ndx and so on..

il try out subjectively:

 code: let m be 'mew not'

field=B={m*n*i(cos@1-cos@2)}/2

where @ is the angle made between the pt of consideration(o) of the field wid the end pt of the solenoid..

so x=Rcot@ where x is dist along hor of endpts from O..

as the pt u r considering is midpt @1=@2 +90

now diff B wrt @ (or x) and chk up..il try to post the whole thing soon

did for solenoid so not applicable for the q

oh shit!!!

yeah ok...neway wat abt the 1st Q??

its ok i guess..but mettalurgy in durgapur is supposed to be gud..

I GOT 4 MARKS INC

2)

well 1st consider indian females:

they make 5 shakes each..tht makes 25 shakes------(1)

american females:

totally 14 shakes/female: 5 wid Ind males + 4 wid american males(excluding husband) and 5 wid ind females(already incl above) so v r refering actually to 9 shakes/american female as the other 5 come in case 1...

so total num of shakes is 9*5=45..

not wat us left is shakes between indian males n american males which is 5*5=25

so total is 25+25+45=95...

where am i wrong???

1) if the q is to make 10 runs in 3 balls or less answer is 36..

if the q is to make 10 runs in exactly 3 balls(wat i mean is match ends only on last ball) then ans is 33..

i dunno where 21 came from!! i used logic..so in 2 diff methods ans comes 33..so i dun think it can be wrong

use L'Hosp:

it is initially 0/0 form...so diff. u get some a/b

now the numerator @ x=0 will be = -1...so denom shud be finite...denom is n*x^(n-1)..for this to be finite @ x=0,n-1 shud be=0 so n=1

3400...

no course alloted