Messages posted by anchitsaini

well , if his answer couldn't do so , lets wait for some other experts :D
(I guess there is one expert who'd surely like to help ) :D :P

widen ur eyes LOL :D :D
I think this qn has been solved quite a few times here only , isn't it or am i mistaken ?

he got solns from his centre , ......
we didn't :(

conjurer again doing bakwaas ??
btw come to gtalk no ?

results out........

i asked the head office, they didn't say any such thing !!!
are u sure ??
or rather can u inquire from the head office too ??

lol , seems i was sleeping !!
otherwise the answer is simply Cdt , and C has been calculated

*misinterpreted*

$TV=a\\ \\ -> PV^2 = aR = const \\ \\ ->x= 2 \\ \\ ->C_v = \frac{R}{\gamma - 1} - \frac{R}{x-1} \\ \\ = \frac{R}{\gamma - 1} - R\\ \\ =R\frac{2 - \gamma}{\gamma - 1} \\ \\ dU= C_v dT = R\frac{2 - \gamma}{\gamma - 1}dT\\ \\ dW=PdV = \frac{RT^2}{a}* \frac{-a}{T^2}dT =-RdT \\ \\ dQ=dU +dW = R\frac{2 - \gamma}{\gamma - 1}dT -RdT \\ \\ = R\frac{3 - 2\gamma}{\gamma - 1}dT$

PS->isn't gamma given , cos otherwise all the above seems to be fruitless

doomed as always , how was urs ?

PAPER 1 - 181

PAPER 2 - 143

I got it this way ->

Just going about it in the backward way solves it ,ie -

After all the cards are on the table , then ->

1 step -> We pick up a card from the table and place it on the top of the pile of cards

2 step -> Now , put the card from the bottom on the top

We find that 1999 comes on top in a stack of ->

3 , 6 ,12 , 24 ,..........., 1536

So the cards left are 2000 - 1536 = 464 on the table

Now , again continuing the procedure we place the card from the table on the top and then the bottom card on the top , until the last card is left which is placed on the top (In this step the bottom card is not place on the top , cos we need to have the original pile)

Hence , total cards above 1999 in original pile are 2*463 + 1 = 927

1) a)

2) d) (from formula)

3) seems d) to me cos->

more the reaction rate, more the particles scattered , more the energy lost , but Reaction Rate is dependant on luminosity which doesn't depend on g

4) initial momentum = m1 v + m2 (-v)

Since , they both are at same velocity (relativistic mass)m1 = m2 , hence initial momentum = 0

so finally -> 0 = m3 v1 +m4 v2 ->

v2= -0.9c (i have not checked up if other answers can coming using relativistic equations .This velocity should satisfy that answer also as when v1 = v2 = 0.9c , both the electrons have same relativistic mass and hence ->

mv1 + mv2 = 0 or v2 = -v1 = -0.9 c)

5)Total energy lost = 2 * 260 = 520 MeV in a time of 1/f = 1/(10000)=10^(-4)s

hence energy lost per second =Power = 520 /10^(-4) = 5.2 * 10^6 MeV /s

ya , but the answer key has some solutions wrong (4-5 i guess )

i guess so

no comments on that , anyways i never say if a paper is easy or not , after all if its easy, its easy for all , finally the percentile will tell that "kaun kitna paani mein hai " :D

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