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You are most welcome to IIT.
Best of Luck.
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Its IUPAC name is Diaminomethanal.
It is also known as carbamide.
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In case of CH2Br2 elctron donating group increses electron density on carbon atom and hence carbon attracts hydrogen atoms towards it.Hence bond length is higher for C2H4.
We are instructed to answer one query at a time.So please post your other queries on a new page.Hope you understand.
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The van 't Hoff factor i is the number of moles of solute actually in solution per mole of solid solute added. Equivalently, i refers to the ratio of true molecular mass to calculated molecular methods by colligative methods.
When solute particles associate in solution, i < 1.
Degree of dissociation  = (i - 1)/(n - 1)
When solute particles dissociate in solution, i > 1.
Degree of dissociation = [i - 1]/[(1/n) - 1]
Otherwise i = 1. = 0
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Actually cut-off marks vary from paper to paper and after the level of paper and according to no. of seats cut-off marks are decided by JEE cell.
You should not worry for cut-off marks, if your preparations are good then you would definitely qualify JEE.
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[x2- ] = -4 0<=x< (-3)
= -3  (-3)<=x<(-2)
= -2 (-2)<=x<(-1)
= -1 (-1)<=x<
= 0 <=x<(+1)
= 1 (+1)<=x<(+2)
= 2 (+2)<=x<(+3)
= 3 (+3)<=x<(+4)
= 4 (+4)<=x<(+5)
= 5 (+5)<=x<(+6)
= 6 (+6)<=x<
Hence integrating x.sin[x2-] in the above intervals sin[x2-] becomes constant and we are left to integrate x .
After simplifying the integral comes out to be
I = [(4-)/2].sin4 + (sin5)/2 + [(2--6)/2].sin6
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Rao Prabhat is exactly right.
In case of mixture of gases Dalton's law of partial pressure should be applied.
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Frequency deviation (?f) is used in FM radio to describe the maximum instantaneous difference between an FM modulated carrier frequency, and the nominal carrier frequency. The term is sometimes mistakenly used as synonymous with frequency drift, which is an unintended offset of an oscillator from its nominal frequency.
The frequency deviation of a radio is of particular importantance in relation to bandwidth, because less deviation means that more channels can fit into the same amount of frequency spectrum. The FM broadcasting range (88-108 MHz) uses a channel spacing of 200 kHz, with a maximum frequency deviation of 75 kHz, leaving a 25 kHz buffer above and below the center frequency to reduce interaction with other channels AM broadcasting uses a channel spacing of 10 kHz, but with Amplitude modulation frequency deviation is irrelevant.
FM applications use peak deviations of 75 kHz (200 kHz spacing), 5 kHz (25 kHz spacing), 2.25 kHz (12.5 kHz spacing), and 2 kHz (8.33 kHz spacing).
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Arvind is correct.
Alternative way :
Flux =  B.dA
[Flux] = [BA]
= [EA/v]
= [VA/vL]
= volt-sec
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For latest news refer to the link
http://www.indiaedunews.net/IIT/IIT_Kharagpur_ready_to_roll_out_reservation_plan_62/
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For derivation refer to the link
http://www.chem.arizona.edu/~salzmanr/480a/480ants/gibshelm/gibshelm.html
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Don has done it perfectly.
Since a + 1/a > 2
Similarly b + 1/b > 2, c + 1/c > 2 , d + 1/d > 2
Hence the expression > (2+1)4
i.e. expression > 34
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Its a simple AP problem.
For the 1st tree distance travelled is (10+10) = 20 m
For 2nd tree = (15+15) = 30 m
For 3rd tree = 40 m ....................and so on
For the 50th tree he only travels from well to tree and not back to well.
Hence for 50th tree distance travelled = 10 + 49*5 = 255 m
Hence distance travelled upto 49th tree = sum of AP
= (49/2)(2*20 + (49-1)*10)
= 12740 m
Hence total distance travelled = 12740 + 255 = 12995 m
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Please post the correct expression.
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Periods of and |sinx| and |cosx| are same i.e.
Hence period of |sinx| - |cosx| is also .
Period of |sinx + cosx| is /2.
Hence period of |sinx| - |cosx|
----------------------- is .
| sinx + cosx |
Lets take example of |sinx|
Its period is and is an even function.
Then according to u its period should become which is wrong.
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