Messages posted by ankitagg

i have done all that .still not getting the answer

(i may be wrong at some step)

so do not post the whole solution.just tell the steps

calculate pH of following solution

a) 40ml of 0.050M Na2CO3 + 50ml of 0.040 M HCl

b)40ml of 0.020M Na3PO4 + 40 ml of 0.040 M HCl

subjective

subjective

one from me

question 5:

for the ellipse

x²/9 + y²/4 =1

.let O be the center and S and S^' be the foci. Then for any point P on the ellipse the value of PS.PS'.d² =____ (where d is the distance of O from tangent at P )

no because if they cut each other then at their intersection point their will be two directions of electric field that is not possible.

upto which rank the selection in hbti kanpur possible

does anyone has the solutions to upseat exam 2009

hey where did u got the solutions

hey accelaration due to gravity wala question in which the value of g at a height was given.anybody getting correct answer

please provide a good site where i can get 2008 uptu papers.

excellent solution

Q. the maximum value of f(x)

Q. the number of solutions of the equation is/are

it is really a good question

my answer is:-

i.e (d)

anyone

answer to q1 is [0,3/2]

since in the interval ,

so

integrating both sides

therefore ans [0,3/2] (pi/2~1.5)

someone please reply

the apparatus consists of three temperature jacked 1L bulbs connected by stopcocks .bulb A contains a mixture of H₂O (g),CO₂(g) ,N₂(g)

at 25⁰C and a total pressure of 564 mm Hg.bulb B is empty and is held at temperature of -70⁰C.bulb C is also empty and is held at

temperature of -190⁰C . the stopcocks are closed and the volume of lines connecting the bulbs is zero. CO₂ sublimes at -78⁰C and N₂

boils at -196⁰C .

Q. the stopcock between A and B is opened and the system is allowed to come to equilibrium .the pressure in A and B is now 219mm Hg.

what are the compositions are in bulbs A and B.

Q both stopcocks are open and at equilibrium pressure throughout the system is 33.5mm of Hg. now the compositions in bulbs A,B,C=?

Q. number of moles of N₂ and CO₂ in above system are

mad 02 :- (b)

mad 03 :-(a),(b)

answer to q15 should be (C) i think

it forms POCl₃ but it is converted in H₃P0₃

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