ans 3)take volume of CH4 = x
N2 = y
CO = z
we are burning in excess of O2 so write the reactions firstly
CH4 + 2O2 -------> CO2 + 2H2O
CO + 1/2 O2 -------> CO2
N2 + O2 wont give u any reaction
we are given x + y + z = 20 ml.............a)
from x ml of CH4 we will get x ml of CO2
N2 will be unreacted
from z ml of CO we will get z ml of CO2 ,
KOH will react with CO2 (as KOH abosorbs carbon di oxide), so if it will abosorb , the volume will become less
it is given derz a contraction of 14 ml
so
x+z = 14 ml...............b)
now see the reactions
x ml of methane will take 2x ml of O2 (2 moles)
z ml of CO will take z/2 ml of O2 (1/2 moles)
total moles of O2 are given 13ml
so
2x + (z/2) = 13................c)
solve these equations......