Messages posted by sunshineson

nice article akri...

This is real Mishra sir..Mr.fnn..pls see his answer! im so sorry u insulted our sir!!!

Sir he is talking about what happens if both d and A are increased by same order.C= Ae/dC remains same

Read straight lines,analytical geometry,slopes of lines in various forms etc..and also limits and continuity,thats good for both NTSE as well as boards and olympiads..

then why is d)2.25 not the answer?

1.    1 lambda
2.     1.5 lambda
3.     2 lambda
4.     2.25 lambda

Q. 80 In Young's double slit experiment a minima is observed when path difference between the interfering beam is: 1. 2. 1.5 3. 2 4. 2.25pls with explanation also..whats relation bw path difference and phase difference?

Thank you Chandrashekhar Limit Sir...

www.ethers.com

u get omega = 3u/root2 x l²

because point mass is "m" and rod is also of mass "m" and the rod is at rest intitially, the velocity of rod becomes 'u' both the rods i mean. now the kinetic energy 1/2 mv² gets equal to the torque T on each rod. equate both of them.

use L= I w equation

take angular momentum L= root( 2 KE) x length of the rod

Now on RHS I= ML²/12 + ML²/4 and w is angular speed.

see 2root(ab)/a+b = 3/5

cross multiply

u get 10 root(ab) = 3(a+b)

square both sides

u get

100ab= 9(a^2 + b^2 + 2ab)

remove 2ab from rhs..it becomes 18ab bcos 9 is outside bracket..take it to other side!! u get 100ab-18 ab= 82ab!!!

SO SIMPLE!!! just solve in a book n see

I think because AC changes its cycle, twice the DC value of current passes through a wire in a given time t. therefore heating will take place more in theAC wire. If cross section is more,AC can be transported effetively. therefore i think its option (b)

Yes...that is correct..but u posted how to convert ethanoic acid to benzene..u can do it via phenol only...other conversions i am not sure

No..you are wrong, dear Punnet!
calculate kinetic energy of the bear at the impact..then substitute in 1/2 mv2= hv..calculate its wavelength..find the corresponding colour of wavelength in electromagentic spectrum! thats the answer! This isnt a lounge,anuj

if the point P(4,-2) is one end of the focal chord PQ of the parabola y2=x, then the slope of the tangent at Q is..............?

if the point P(4,-2) is one end of the focal chord PQ of the parabola y2=x, then the slope of the tangent at Q is..............?

Let KE= 1/2 mv²

therefore

rate of imparting KE

d/dt KE= d/dt (1/2 Mv²)

Let total mass be M which equals m multiplied by distance travelled l.

therefore d/dt KE= 1/2 .m v² dl/dt

but dl/dt= velocity

this means d/dt KE= 1/2 m v³

1/2 m v³ is the ans.

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