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because H2SO4 reacts itself with KI so formation of K2SO4 and HI.this HI is a redusing agent so it reacts with H2SO4 to form SO2 and I2 .SO it cannot use in this reaction because it does not exist as H2SO4.
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while in case of AgCN it is polar covalent so it is not enough polar so attachment site is only lone pair so by reaction with RX it form mainly isocyanides .
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KCN is ionic compound it form CN negative ion which is ambident nucleophile so there is two site for attachment one is negative charge at carbon while second is lone pair of nitrogen.negative chrge is prepared so it is more reactive so electrophile R+attach from this side to form cyanides.
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ethyne reacts with O3 ,H2O and Zn to form CHO-CHO by reductive ozonolysis ,this reacts with 2 mole HCN and acidic hydrolysis to form tartaric acid .it contain chiral carbon so optically active in nature but if it is meso than it is inactive.
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Ethyne reacts HCHO in presence of Cu+ to form propergyl alcohol IUPAC name is Prop-2-yne 1-ol
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c.ethene reacts with chlorine polar than KCN and water to form (CH2)2(COOH)2succinic acid which on heating form succinic anhydride,this reacts with ammonia to form amide and than Br2 called N-Bromosuccinimide used as free radical substitution reagent at allylic and benzylic position.
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2.a.ethyl chloride reacts with sodium-lead alloy form TEL b.ethyl chloride reacts with Mg to form ethylmagnesiumchloride and than reacts with PbCl4 to form TEL
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1.benzene reacts with chlorine polar to form chlorobenzene,this reacts with chloral CCl3CHOin presence of con.H2SO4 formation of p,p/dichlorodiphenyltrichloroehane(DDT)by removal of water.
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SOME TIME IT INCREASES REACTIVITY OF CHEMICAL REACTION ALSO BY THE BULKYNESS OF GROUP.for example if we compare basic nature of N,NDimethylaniline and 2,6dimethylN,NDimethylaniline ,later one is more basic because bulky alkyl group create steric hindrance due to this amino group come out of the plane and its lone pair do not take part in resonance so basic nature increases.
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WHEN ONE CARBON ATTACH WITH THREE CARBON CALLED TER.BUTYL GROUP (CH3)3C-
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when one carbon attach with two methyl group is called isopropyl gr(CH3)2CH,when one carbon attach with one ethyl and one methyl called sec.butyl(ch3)C(C2H5)- ,WHEN ONE CARBON ATTACH WITH FOUR CARBON IS CALLED NEOPENTYL GROUP(CH3)4C-
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as the size of alkyl group increases reactivity of reaction decreases while some time increases also.for example 3 amine are less basic than 2 amine due to steric factor because as the size of alkyl group increases reactivity decreases.reactivity of carbonyl compound towards nucleophilic addition reaction also decreases due to steric factor.HCHO>CH3CHO>CH3COCH3
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CH3CH2O->CH3CH2S->CH3COO-,in CH3COO-resonance so minimum nucleophilic nature while in S there is vacant d orbital which decreases nucleophilicity.in second example C6H5O- is poor nucleophile due to resonance because in other resonance is absent
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i m regularly tell that to improve your organic you concentrate your basic mechanism of organic ,omprove type of reaction and reagents.some effects like I efect,resonance ,electromeric efeect,acidic and basic strength type question .refer some good book any basic book which you like.
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sorry answer is 4-phenyl 3-alkyl 2-butanol,above answer is not correct.
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fission of cyclic ether takes place in two different medium ,if it is acidic than intermediate is carbocation formation while in basic medium sn2 mechanism so less crowded side from nucleophile atacks.in this reaction acidic medium so carbocation intermediate so RMgX R anion attack from phenyl side due to more stability so answer is 3-phenyl 2-alkyl 1-propanol
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if we consider other example that i-cyclobutylethene reacts with dilute H2SO4 to form cyclopentanol by ring expansion here addition of water takes place with intermediate carbocation.
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smaller rings are less stable than larger ring due to ring strain so these tends to convert into larger ring by ring expansion .for example when cyclobutylmetanol reacts with con.H2SO4 to form cyclopentene by ring expansion.
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to find out the hybridisation of any species use formula ,steric number =no.of sigma bond +lone pair if it is 2 hyb is sp,3 sp2,4 sp3,5sp3d ,6sp3d2 ,7sp3d3.if there is alkane it is sp3 if there is triply bonded alkyne hyb is sp so in this question correct option is b
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by hydrolysis both chlorine are substituted by -OH group .one carbon with two -OH group is unstable so water comes out and ketone formation takes place soproduct is 3-methyl buatane 2-one
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