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we're differentiating w.r.t h, wont we assume x constant

NH3+ > NO2 > CN > (SO)₃H > CHO > COR> COOH >COCl > COOR > CONH₂ > F > Cl > Br > I > OH > OR > C₆H₅ > H

(given in fiitjee)

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if we have a function f(1+h/x), if we differentiate this w.r.t h,is the ans,f`(1+h/x)*1/x?

so ans is A or D (should be D?)

umm, im not sure, but giving it a try

if d<=dw, the block will not sink into the fluid due to which the layers in contact with it wont be displaced(they would be displaced, but would be at rest since block would remain at one position),

if d>dw, then the block would hv gone and hit the surface, and alongwith it, the layers in contact with the block would hv been displaced downwards(i.e. attained a velocity), due to viscoscity, the adjacent layers would hv also started moving and equilibrium would hv been disturbed

(i think...i just read fluids today, so im not too sure...)

umm, no offence/sarcasm,
but, nitigya, u hv assumed w=(k/m)^1/2, and derived the same thing...(in the x=Asinwt)

plz correct me if im wrong

w is just a variable which is analogous to the angular velocity of an object,

in derivation of time period in shm:
T=2pi/(k/m)^1/2

and for a particle moving in a circle(also doing periodic motion),
T=2pi/w, where w is angular velocity of particle
therefore for convenience we write w=(k/m)^1/2

NOTE: It does not mean the object doing shm has an angular velocity w, it is just a variable...

w in shm is also called angular frequency

w=sqrt(a/m)

COME ON, PLZ........

nice...

anyone plz, i need help urgently

A particle of mass m moves with a force varying with velocity as F=a(yi - xj), a is a positive const, and i & j are unit vectors along x and y axes. At the initial moment(t=0), the particle was located at x=y=0, and had a velocity Vo directed along the unit vector j. Find the law of motion x(t), y(t) of the particle, and also the equation of its trajectory

can anybody plz tell wat im doing wrong

my answer:

F=ayi - axj

a=ay/m i - ax/m j

Ax=ay/m (acc in x dir)

Ay=-ax/m ---- 2 (acc in y dir)

substitute x=Asinwt in 2

integrate 2,

we get Vy=aAcoswt/wm

at t = 0,

Vo=aA/wm

or A=vo/w (where w²=a/m)

and let y=Bsinwt

therefore Vy=bwcoswt

Vy=w(B²-y²)^1/2

or Vo = wB (substituting initial conditions)

now we have A and B,

on squaring and adding, we get

x² + y² = (Vo/w)²

but the answer given is (x-vo/w)² + y² = (Vo/w)²

can anyone please tell me what im doing wrong...

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thanks a lot both of u ^^

max value of coswt(1+4sinwt)

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