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dats y its stored in kerosene......
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it is to release the ions........otherwise it will remain a cpd itself...
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hey in nit trichy,all r gud.......sastra comp sci is gud.....dunno abt d rest
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trichy of course...................!!!!!!!!!!!!!!!!!!!!!
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ya more the no. of Cl-O bonds more is the acidity.
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1)CsI-bcoz both of the atoms r large in size and weak forces bind them.so their lattice E is less.Li and F are very small so the forces of attraction are strong and so lattice E is high.
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yup its NH4+ .ts not that N is deficient of e- but has used its e to accept a H+. so it can regain its e- by releasing a H+.but the others r diff.BCl3 is a lewis acid.Hg2+ is stable in this config.CH3+ cannot accept e- due non availability of d orbitals in C.
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1M = n1/0.1 => n1 = 0.1
similarly n2 = 0.4 , n3 = 0.9
total no. of moles of HCl = 1.4
1M = 1.4 / x => x = 1.4L of water shd be added.
am i right?
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in atomic structure, 1) if n = 4, l = 0, 2) if n = 3, l = 2
which has more energy? by using bohr-burry rule 2) has more energy, but if we see the quantum no. 1) has more energy. Confusing!!?? which one should we use & which is the right answer? !!!!!!!!!!!!!
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for the reverse:
1)convert NH2 to N2Cl and add H3PO3 and get tribromobenzene(NH2 grp is removed).
2)now convert Br to OH by Dows process(add NaOH at 623K).
3)now add Zn dust,ZnO is removed and u get benzene
rate if useful
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simple.....
sin(x+y)-log(x+y)=0
diff, cos(x+y) * (1+y') - (1/(x+y) )*(1+y')=0
(1+y')[cos(x+y)-(1/(x+y))=0
y'=-1
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wt=25*300/100 + 40*400/100 =75+160=235g
mass%=235*100/700=33.57%
am i right??????
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how do v find the eq R in infinite r combinations.plz give a general method for these.i am stuck half way thru. !!!!!!!!!!!!!!!
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when the capacitor is grounded the grounded plate is at potential =0.but the other plate will have its charge and also a potential due to it.since S2 is not closed,thus the potential of the inner plates remain 30 and 20 only.
V1=30-0=30
V2=20-0=20
thus ans is d)
hope this helps
rate if its correct
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i dunno about brilliant as i used fiitjee only.but the books u hv r sufficient for jee.practise every problem from them.
ALL THE BEST
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@ karthik2007
i too did it in the same way and got 3R/4.also there is an option like that. but the book gives an xplanation for its ans which i dont understand.not even a bit.the eq. circuit is fully confusing
wat do i do now???????
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nope the ans is 5R/6
dunno how
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find eq resistance between A and B.each is equal to R. !!!!!!!!!!!
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I SUPPORT CHENNAI SUPERKINGS!!!!!!!!!!!!!! AND KOLKATA KNIGHT RIDERS!!!!!!! NO MATTER WHAT HAPPENS ,ITS ALWAYS THE KNIGHTS WHO FIGHT AND THE KINGS WHO RULE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!
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1) the chord subtends an angle of 45 at the centre(it is a theorem)
area of the sector=(45/180) * pie *R^2=(pie/4)*R^2
remaining area=pie*R^2-(pie/4)*R^2=(3pie/4)*R^2
area of the triangle made by the chord at the centre=
(1/2)*R^2*1/root 2
net area=(3pie/4)*R^2-R^2/2 root 2
plz correct me if m wrong
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Vriti Edustore
