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please some one tell me where i hv done wrong in my above posted solution i need to know what is wrong in my procedure please reply
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it can be a>c>b
a unsymm+ electron density more due to more alkyl grp. atttched
c no resonance=> more electron density
b lp_singlebond_double bond res => electron spread throughot the molecule so less electron density

plz rate if usefull

please some one tell me where i hv done wrong in my above posted solution i need to know what is wrong in my procedure please reply
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please someone do tell what is wrong in my method

what is wrong in my method ???

= dV/v(dT)

v(dT) = dV

nRT(dT)/P = dV

nRT(dT)/P =

dV

nRT²/2P = V

nRT²/2P = nRT/P

= 2/T

THE ANS IS 1/T

coefficient of volume expansion given by

=(dv)/v(dT)

coeff. of vol exp. for ideal gas where pressure is constant is:

a1/T

b2/T

c-1/T

d -2/ T

some one plz do solve this
the question is very correct(esp for computeroo1)

how many of you all have received iit-jee 2008 admit cards.

kgp zone especially.

i hvnt yet received mine!!!

option (a) n (b) are in the pic

(c) 3BIL
(D) 0
please solve

yup understood thanks

thin walled, so why B =0?
n i hv rated u

solve

please reply quick ans is c

thanks