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Soumya Ranjan Bairishal   Soumya Ranjan Bairishal is offline Soumya Ranjan Bairishal's messages in the community
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Catalogs Discussion Forums -> About IITs and JEE -> IIT 2009 -> Go to message
This Post 2 points    (0 Olaaa!! Perrrfect answer.   in 1 votes )   [?]

IIT 2009  not subjective No Screening


Exam on 12 April 2009


Application form sale begins on 19 november 2008


Visit Link : http://www.iitkgp.ernet.in/jee/


Rate me if useful
Catalogs Discussion Forums -> Coaching Institutes & Course Material -> INTERESTING CONTEST BETWEEN P-BAHADUR VS R.C.MUKHERJEE -> Go to message
This Post 2 points    (0 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
I will go for RCM
Catalogs Discussion Forums -> Trignometry -> inverse -> Go to message
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fantastic...
Catalogs Discussion Forums -> Differential Calculus -> Maxima & Minima Question... -> Go to message
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Thanx Magiclko.....
Catalogs Discussion Forums -> Analytical Geometry -> Is matrixs is important topic in Maths for IIT or AIEEE? -> Go to message
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just one or 2 Qs
Catalogs Discussion Forums -> Differential Calculus -> Maxima & Minima Question... -> Go to message
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Question in R.D.Sharma, Vol-I (CBSE) page-18.63 Q.No.-36
The strength of a beam varies as the product of its breadth and square of its depth. find the dimensions of the strongest beam which can be cut from a circular log of radius a.

please give detailed solution...RATES  assured
Catalogs Discussion Forums -> Differential Calculus -> question -> Go to message
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use ILATE
Catalogs Discussion Forums -> Lounge -> Make Friends -> Go to message
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papu_srb@yahoo.co.in

srbairishal@gmail.com
Catalogs Discussion Forums -> Lounge -> Congratulate Koni!! -> Go to message
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BRAVO !!!! Keep it Uppppp...
Catalogs Discussion Forums -> Differential Calculus -> 1)Differentiate y=5log5(1+tanX) (It is log to the base 5) 2)logx(a) -> Go to message
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1) y = 5log5(1+tanx)
    y =1+tanx
  
differentiating both sides

dy/dx = sec2x  (read as sec square x)

2) y = logx(a)
      = log a/ log x
 differentiating both sides
dy/dx = x(log a)
Catalogs Discussion Forums -> Differential Calculus -> Maxima & Minima Question... -> Go to message
This Post 0 points    (0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Question in R.D.Sharma, Vol-I (CBSE) page-18.63 Q.No.-36
The strength of a beam varies as the product of its breadth and square of its depth. find the dimensions of the strongest beam which can be cut from a circular log of radius a.

please give detailed solution...RATES  assured
 
 
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